Answer:
0.66 gal.
Step-by-step explanation:
The following should apply:
C1 * V1 = C2 * V2
we have that C1 is 0.1, that C2 is 0.3 and that V1 is equal to 2 gal
replacing the values we have that:
0.1 * 2 = 0.3 * V2
reorganizing the equation we have:
V2 = 0.1 * 2 / 0.3 solving this remains 0.66.
It means that the amount of solution 2 is 0.66 gal.
Can u give us more information please
I think you meant to say n = 11. If so, then you are correct and it leads to the proper length for FG, which is 16 units. Nice work.
What is the mean average<br>
14, 12, 9, 2, 3, 1, 1<br><br>
10,10,10,5,9,12,12,24,8,31,3,10
Orlov [11]
Answer:
20.89
Step-by-step explanation:
x f fx
1 6 6
2 4 8
3 5 15
4 3 12
5 3 15
6 2 12
8 1 8
9 2 18
10 4 40 average=fx/f
12 3 36 = 961/46
14 2 28 = <u>20.89</u>
19 1 19
24 1 24
26 1 26
31 1 31
32 1 32
56 1 56
67 1 67
100 1 100
102 1 102
150 1 150
156 1 156
total: <em>46</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>961</em>
A) See picture for the table.
To make the table, multiply 47774 by 1.5% to get total that have diabetes and multiply 5855 by 2.5% to get total unemployed that have it, then using subtraction fill in the other squares of the table.
B)
Hypothesis:
H0: No association between employment and diabetes.
H1: Association between the two
Using a graphing calculator or Excel, run a chi-test.
Chi squared equals 31.844 with 1 degrees of freedom.
The two-tailed P value is less than 0.0001
With this information we can reject the null hypothesis and conclude there is an association between diabetes and employment.
C)
Although there is a statistical significance, there really is no practical significance between an incidence rate of 1.5 or 2.5%
