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2 years ago

How do you find the surface area

Mathematics

2 answers:

kiruha [24]2 years ago

5 0

In order to find the surface area you find the area of the 2 sides.

Illusion [34]2 years ago

3 0

You find the area of each side of the shape and once you do that you add them all up.

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For the function f(t) =Pe^rt , if P= 7 and r= 0.07 then what is the value of f(7) to the nearest tenth?

White raven [17]

Answer:

A. 11.4

Step-by-step explanation:

$f(t) = P e^{rt}$

Data:

P = 7

r = 0.07

Calculation:

$\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}$

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What is the simplified form of 5x(2x^2)

lukranit [14]

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2 years ago

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2 years ago

Which of the following equations is equivalent to x - y = 6?

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I believe the answer would be A. 2x-y=6 :)

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Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

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3 years ago