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Nataly [62]
2 years ago
13

Please help me pleaseeee I’ll mark brainliest for the first person who answers no joke

Mathematics
1 answer:
Tresset [83]2 years ago
8 0

200=10c

c=20

hope it helps

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Given the points (3, 2) and (6, 4), which of the following are true about the line passing through these points?
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I don't know what 'which of the following' is referring to, but the line has a positive slope, goes through the origin, and has a slope of 2/3.
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3 years ago
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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet
Dima020 [189]
Let's find the perimeter of the window.

The bottom side is x. The left and right sides make 2y.
The perimeter of a circle is 2\pi r, so the perimeter of a semicircle must be \pi r, The radius is \frac{1}2x, so that gives \frac{1}2\pi x for the curve. All of that is equal to 12.

x+2y+\frac{1}2\pi x=12

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2y=12-x-\frac{1}2\pi x

y=6-\frac{1}2x-\frac{1}4\pi x

Now that we have a value for y in terms of x, we can find the area in terms of x.

The area of the rectangle is going to be xy, which then becomes

A_r=x(6-\frac{1}2x-\frac{1}4\pi x

A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2

The area of the semicircle is going to be \frac{1}2\pi r^2.

Since r=\frac{1}2x, A_{sc}=\frac{1}2\pi (\frac{1}2x)^2.

A_{sc}=\frac{1}2\pi \frac{1}4x^2

A_{sc}=\frac{1}8\pi x^2

Now let's add the areas of the rectangle and semicircle.

A=A_r+A_{sc}

A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2

A=6x-\frac{1}2x^2-\frac{1}8\pi x^2

If you wanted to factor out \frac{1}8 like you did, this would become

\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}

Now what we want to do is find what x is when A is at its highest point, Once we have the value for x we can also find the value for y, of course.

Let's put our equation in the general form of a quadratic.

A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x

Now we can use the vertex formula x=\frac{-b}{2a}.
(a and b refer to ax^2+bx+c.)

x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}

x=\frac{-6}{-\frac{1}4\pi -1}

x=\frac{-24}{-\pi -4}

\boxed{x=\frac{24}{\pi +4}}

Now let's plug that in for y=6-\frac{1}2x-\frac{1}4\pi x.

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use x\approx3.36059492.

y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)

<span>y\approx6-(1.68029746+2.63940507809)

</span><span>\boxed{y\approx1.68029746191}

Let's take our answers for x and y and round to 2 decimal places.

\boxed{x\approx 3.36\ ft}

\boxed{y\approx 1.68\ ft}</span>
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3 years ago
C = 3/4y + b, solve for b
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Answer:

b = c - 3/4y

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move 3/4y to the other side with c:

c - 3/4y = b

b = c - 3/4y

4 0
2 years ago
Find constants a and b so that the minimum for the parabola f(x)=x^2+ax+b is at the point (6,7)
Blizzard [7]
To find the minimum, take the derivative of the function and equate to zero:

f(x) = y = x² + ax + b
dy/dx = 2x + a = 0
Substitute x =6:
a = -2x
a = -2(6)
a = -12

Then, substitute x = 6, y = 7 and a = -12 to find b.

7 = (6)² -12(6) + b
7 + 36 = b
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3 years ago
Lorenzo drew 3 triangles, 4 rectangles, and 7 arrows in a set of 20 shapes. The only other type of shape in the set is a circle.
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Answer:

\large\boxed{6/20}

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In this question, we're trying to find how many circles are there and represent it as a fraction.

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  • 7 arrows
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3 tiangles + 4 rectangles + 7 arrows = 14 shapes

We know that there is suppose to be 20 shapes, this means that the remaining amount would be circles (6 circles)

We now know that there are 6 circles and 20 shapes in total.

This means that the fraction that would represent circles is 6/20

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
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3 years ago
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