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Damm [24]
4 years ago
10

How do you solve: f(x) = -x2e-x +2xe-x , finding the zero's of f.

Mathematics
1 answer:
Maksim231197 [3]4 years ago
7 0

Answer:

0 and 2

Step-by-step explanation:

f(x) = -x^2e^{-x}+2xe^{-x}

To find zeros set f(x)=0  and solve for x

0 = -x^2e^{-x}+2xe^{-x}

0 = -e^{-x}(x^2-2x)

now factor out x

0 = -xe^{-x}(x-2)

set each factor =0 and solve for x

x=0

-e^{-x}=0 no solution for x

x-2=0, x=2

zeros of f  are 0 and 2

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