MCV = Hct × 10/RBC (84-96 fL) •Mean corpuscular Hb (MCH) = Hb × 10/RBC (26-36 pg) •Mean corpuscular Hb concentration (MCHC) = Hb × 10/Hct (32-36%) A rapid method of determining whether cellular indices are normocytic and normochromic is to multiply the RBC and Hb by 3.
Answer:
Option b) chromosomes
Explanation:
The correct answer for the given question is option (b) Chromosomes.
The whole structure of the sperm contains the various components which are
as follows:
The head of the sperm contains the nucleus and the chromosomes
The neck contain of the sperm contains the mitochondria
the tail of the sperm contains the flagella.
Answer:
"My child will be asked to stand upright, arms stretched above the head."
Explanation:
The adolescent client should be leaning forward at the waist with arms hanging down; upright with arms stretched above the head would not allow proper screening.
Answer:
You haven't added the questions-
