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defon
3 years ago
15

What is 3.875 rounded to the nearest cent?

Mathematics
1 answer:
Ronch [10]3 years ago
5 0
The answer should be 3.88 because when people talk about ''cent'' that usually refers to nearest hundredth so round it and that would be 2 decimal spaces so go from left to right and count twice after 3, and round <u>7</u> up by 1 and that would be 8, so 3.88 should be it.
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Find the slope. <br><br>a<br>A. undefined<br><br>B.0
Oduvanchick [21]
It would be 0 because as you go along it doesn't go up but keeps moving. An undefined slope is up and down/vertical.
3 0
3 years ago
Read 2 more answers
Use four rectangles to estimate the area between the graph of the function f(x) = V3x + 5 and the x-axis on the interval[0, 4] u
yuradex [85]

Answer:

  12.123

Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

  f(0) +f(1) +f(2) +f(3)

As the attachment shows, that sum is ...

  area ≈ 12.123 . . . square units

__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.

7 0
1 year ago
MEDAL !!! TRUE OR FALSE. Jonathan is catering an event for one of his clients. He has a maximum of $200 to spend on appetizers.
DochEvi [55]

182.5 US dollars so yes

the answer is True

5 0
3 years ago
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
If $120.00 is borrowed for 3 years at 5% how much interest will be generated by the end of the loan? please answer will mark bra
Doss [256]

Answer:

I = prt / 100

120x3x5 / 100

= 18

6 0
3 years ago
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