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malfutka [58]
3 years ago
14

"The ability to create methods with the same name that are in different classes" is known as ________.

Computers and Technology
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

Polymorphism

Explanation:

Polymorphism is the ability of an object to take multiple forms. It is an important concept of Object Oriented Programming. Polymorphism is used in Object Oriented Programming when a reference of a parent class is used to refer to a child class object. It allows to perform a single action in different ways. For example a person can possess different characteristics at the same time. A person can be a father, husband, employee or student. The same person can have different behaviors in different circumstances.

Example:

Suppose there is class Animal with a procedure sound(). This method can have different implementation for different animals. For this purpose lets take two derived classes Cow and Cat that extend the Animal class (parent/base class). Now the method sound() can be used in different ways for Cow and Cat.

public class Animal{

public void sound(){

System.out.println("Animal is making a sound");  } }

public class Cat extends Animal{

 public void sound(){

  System.out.println("Meow");     } }

The output is Meow. The same method sound() is used for cat subclass.

public class Cow extends Animal {

  public void sound(){

    cout<<"Mooo";  }}

The output is Mooo. The method sound() is used for a Cow subclass which returns the sound of Cow in output.

So the same function i.e. sound() behaves differently in different situations which shows Polymorphism.

Polymorphism has 2 types.

One is compile time polymorphism which is called overloading. In method overloading a class can have more than one functions with same name but different parameters. Methods can be overloaded by change in number or type arguments. For example overloading a function method() can take the following forms in which the name remains the same and parameters are different.

void method(int a)

void method(float a)

void method(float a, float b)

Second type is run time polymorphism which is called overriding. Method overriding is when a method declared in derived class is already present in base class. In this way derived/child class can give its own implementation to base/parent class method. Method present in base class is called overridden and that in subclass is called overriding method. The example of Animal Cow and Cat given above is an example of overriding.

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Alinara [238K]

Answer:

Explanation:

I noticed the \n, \n will cause the new line break, delete it.

try code below:

<em>System.out.println(" " + " " + "NO PARKING");</em>

<em>System.out.println("2:00 - 6:00 a.m.");</em>

5 0
2 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
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So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


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