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erastovalidia [21]

3 years ago

6

Can a irrational number be a rational number?

1 answer:

otez555 [7]3 years ago

3 0

No, an irrational number cannot be a rational number

If they could there would literally be no point in the term “irrational number” existing

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What's the next number 2 3 5 7 11 13 17

maw [93]

The sequence 2, 3, 5, 7, 11 are the first five prime numbers. A prime number is a positive integer which has exactly 2 positive integer factore, one factor being 1 and the other factor is the positive number itself. So the next prime numbers after 11 are 13, then 17, 19, 23, 29, 31, 37, 41, 43

4 0

4 years ago

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Determine the measure of the missing angle in the figure below.

bearhunter [10]

Answer:

Step-by-step explanation:

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3 years ago

Andre drives a bike for 4 hours covering 160 km. Find the distance covered by him in 7 hours.

swat32

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I think is 280km :))))))

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2 years ago

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(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

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3 years ago

What is 5 2/9 plus 7 5/15

alina1380 [7]

47/9+110/15=705/135+990/135=1695/135=12 15/27

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3 years ago

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