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Snowcat [4.5K]
3 years ago
9

What is the area of this rectangle?

Mathematics
2 answers:
Akimi4 [234]3 years ago
5 0

8 \times 5 = 40 \div 2 = 20
Lunna [17]3 years ago
4 0

Answer:

40

Step-by-step explanation:

Remember the Area formula:

Area = b * h = base * height

Plug in 8 for base, and 5 for height

Area = 8 * 5

Area = 40

~<em>Senpai</em>

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If f(x) = x2 + 4x - 12, find f(2).
Illusion [34]

Answer:

-3

Step-by-step explanation:

Please write this as  f(x) = x^2 + 4x - 12.  "x^2" represents "the square of x."

f(2) is the value of this function when x = 2:

f(2) =  f(2) = (2)^2 + 4(2) - 12  =  9 - 12 = -3

7 0
3 years ago
(b-2)x= 8
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

(2-2)x = 8

(0)x = 8

x = 8/0

no solution

6 0
3 years ago
Solve for x and y
bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0
2 years ago
Write the equation of each line using the given information.
Leni [432]

a) x – 2y + 6 = 0 b) x + y = 1 c) y = 1 d) y = -3x + 8

<h3><u>Solution:</u></h3>

<em><u>a. The points (-4,1) and (2,4) both lie on the line</u></em>

The general line equation on which (a, b) and (c, d) lies is:

y-\mathrm{b}=\frac{d-b}{c-a}(x - a)

Here the given points are (a, b) = (-4, 1) and (c, d) = (2, 4)

Thus the required equation is:

y-1=\frac{4-1}{2-(-4)}(x-(-4))

On solving we get,

\begin{array}{l}{\rightarrow y-1=\frac{3}{2+4}(x+4)} \\\\ {\rightarrow y-1=\frac{3}{6}(x+4)} \\\\ {\rightarrow 2(y-1)=1(x+4)} \\\\ {\rightarrow 2 y-2=x+4} \\\\ {\rightarrow x-2 y+6=0}\end{array}

<em><u>b.) m= -1 and the point (2, -1) lies on the line</u></em>

The equation of line in point slope form is y – b = m(x – a)  

where m is slope and (a, b) is a point on it

Here m = -1 and (a, b) = (2, -1)

Thus the required equation is:

y – (-1) = -1(x - 2)  

y + 1 = -x + 2  

y = -x + 2 -1  

y = -x + 1

<em><u>c. )It has the same slope as y = 5 and passes through (1, 1)</u></em>

our line has same slope with y = 5, then our equation would be y = k  and it passes through (x, y) = (1, 1) so, then by substitution

1 = k

k =1  

Then our equation will be y = k

y = 1

<em><u> d. ) m= -3 and it has a y-intercept of (0, 8)</u></em>

line equation in slope intercept form is y = mx + b where m is slope and b is y – intercept.

Then, our equation will be y = -3x + 8

We took y- intercept = 8 as it is the value of y when x = 0

6 0
3 years ago
What are the intercepts of the equation 4x+6y+2z=12?
Bond [772]

Answer:

The answer is D

6 0
3 years ago
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