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3 years ago

5

What would the constant ratio be? And am I correct about it being geometric?

1 answer:

andrezito [222]3 years ago

4 0

Answer:

No it would be a Arithmetic sequence because it’s adding, not multiplying.

Step-by-step explanation:

Arithmetic sequences use addition, so each term is a constant amount (common difference) more or less than the last.

Geometric sequences use multiplication, so each term is multiplied by a constant amount (common ratio) to get the next one.

Plz Brainly :’D

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Substitution: y-2x=-6 and 5x-y=9

Dmitrij [34]

<span>y-2x=-6 and 5x-y=9

step 1: isolate y in the first equation

y = 2x - 6

step 2: substitute the y value on the 2th equation:

5x-(2x-6)=9

step 3: solve the present equation:

5x - 2x + 6 = 9
3x = 9-6
3x = 3
x = 1

step 4: get the y value by replacing the value of x in </span>y = 2x - 6:
<span>
y = 2*1 - 6
y = 2 - 6
y = -4

S={1, -4}

</span>

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3 years ago

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Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

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3 years ago

Consider a triangle ABC like the one below. Suppose that a=51, b=16, and A=108. (The figure is not drawn to scale.) Solve the tr

Blababa [14]

Answer:

B = 17.4°

C = 54.6°

c=43.7

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3 years ago

The table below represents a function. Which of the following equations could be its function rule?

worty [1.4K]

Answer:

$y=2x-2$ is the required equation.

Therefore, the second option is true.

Step-by-step explanation:

We know that the slope-intercept form of the line equation of a linear function is given by

$y=mx+b$

where m is the slope and b is the y-intercept

Taking two points (0, -2) and (1, 0) from the table to determine the slope using the formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(0,\:-2\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)$

$m=\frac{0-\left(-2\right)}{1-0}$

$m=2$

substituting the point (0, -2) and the slope m=2 in the slope-intercept form to determine the y-intercept i.e. 'b'.

$y=mx+b$

$-2 = 2(0)+b$

$-2=0+b$

$b=-2$

Now, substituting the values of m=2 and b=-2 in the slope-intercept form to determine the equation of a linear function

$y=mx+b$

$y=2x+(-2)$

$y=2x-2$

Thus, $y=2x-2$ is the required equation.

Therefore, the second option is true.

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shtirl [24]

Given:

22 gallons of 16% ammonia

24% ammonia

Find:

Number of gallons of water to remove

Solution:

Let n = number of gallons needed to obtain 24% ammonia

22 gallons (0.16) = n (.24)

<span>N = 14.67 gallons of water</span>

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3 years ago

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