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Liono4ka [1.6K]
4 years ago
10

I need the steps for 37

Mathematics
2 answers:
AysviL [449]4 years ago
7 0
There is no picture
Fynjy0 [20]4 years ago
5 0
Ok, so first the question tells us that triangle WLJ is congruent to triangle QBV. So, from this we know that side WJ is congruent to side QV. We also know that side LJ is congruent to side BV. So we put this into a ratio.
Then, we solve for x by algebra.
For the sides LJ and BV, it's really simple because there is no expression to work out, so x is equal to five
Whereas, for the sides WJ and QV, we solve the equation and x is equal to two. But, we are given the expression that side WJ is x+6. Using x (which is 2), we do 6+2 which is eight.
The scale factor is 1 (8/8 is one) ( or you could do 5/5 which is also one)
:)

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3x-x-5=2(x+2)-9 what is the answer to x
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(-infinity, infinity) or all real numbers

Step-by-step explanation:

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Please help me with this I don't understand it.
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4 years ago
Read 2 more answers
1×12 2×11<br>what is itor
Sergeu [11.5K]

1 Simplify

1×12



12×(2×11)



2 Simplify

2×11

12×22



3 Simplify


264



or


1 x 12 x 2 x 11 =

[Answer] 264

6 0
4 years ago
What’s up solution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0
ladessa [460]

Answer:

x = cuberoot( -9/8)= -1.04004  or  x = cuberoot(1/2)=0.7937

Step-by-step explanation:

let y = x^3 + 1

we have:

16*(y) ^2   -  22 (y)  - 3 = 0

16 = 2* 8

-3 = -3* 1

8*-3  + 2 = -24 + 2 = -22

Factor as  (8y + 1)(2y - 3) =  16 (y)^2 - 22(y) - 3 = 0

so  (8y + 1) = 0   or   2y - 3 = 0

y = -1/8   OR   y = 3/2

with  y = x^3 + 1

solve for x

-1/8 =  x^3 + 1

x^3 = - 9/8

x = cuberoot( -9/8)

about x = -1.04004

or   3/2 = x^3 + 1

1/2 = x^3

x =  cuberoot( 1/2 ) = 0.7937

3 0
3 years ago
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