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ollegr [7]
3 years ago
8

The system of equations is graphed in the figure. What is the solution of the system ?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0
The answer is (3,-2)
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Step-by-step explanation

Add all values and divide by the total amount of addends.

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a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

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Step-by-step explanation:

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viva [34]

Answer:

Below

Step-by-step explanation:

First we combine your first set of terms,

7b^2 + 2b^2 = 9b^2

There's a subtraction hidden in there!

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Next we do the same thing for the second term,

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but there's a subtraction in the expression!

10b - b = 9b

Then we finish with our third term

6 + 5 = 11

Answer:

6b^2 + 9b + 11

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3 years ago
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