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3 years ago

Who are from gondia

Mathematics

1 answer:

iVinArrow [24]3 years ago

6 0

Answer:

Gondia is a city and municipal council in the Indian state of Maharashtra which serves the administrative headquarters of the eponymous administrative district. Gondia is also known as Rice City due to the abundance of rice mills in the area.”

Found this online :)

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Assume that Emily (who has CF, a recessive disease (aa)) decides to have children with a man who does not have CF and who has no

alukav5142 [94]

Answer:100%. Probability

Step-by-step explanation:

Emily = aa

Man = AA

After crossing the two, the result wI'll be Aa, Aa, Aa, Aa

Since every result has a carrier(a) in it, makes it 100% probability.

7 0

3 years ago

Citizens less than 18 years old are not allowed to vote define a variable and write an inequality for the ages of citizens who a

Marrrta [24]

Answer:

$x < 18$

Step-by-step explanation:

We are given the following information in the question:

"Citizens less than 18 years old are not allowed to vote"

We define a variable x such that x represents the age of citizens.

We have to write a relationship with the help of an inequality for the ages of citizens who are not allowed to vote.

Citizens less than 18 are not allowed to vote.

So x should be less than 18.

This can be written as:

$x < 18$

is the required inequality for the ages of citizens who are not allowed to vote.

8 0

3 years ago

Candy Crunchers wants to see if their new candy is enjoyed more by high school or middle school students. They decide to visit o

Goryan [66]

all students who attend 1 MS and 1 HS in Miami, FL.

This is because they only surveyed 1 ms and 1 hs

Good luck! please vote me brainliest

5 0

3 years ago

Read 2 more answers

Use the figure below to find the exact values of the double angles.

scZoUnD [109]

Right away, we know that

$\cos\beta=\dfrac{16}{20}=\dfrac45$

which means

$\sin\beta=\sqrt{1-\cos^2\beta}=\dfrac35$

Then

$\cos\beta=\cos2\left(\dfrac\beta2\right)=\cos^2\dfrac\beta2-\sin^2\dfrac\beta2$

$\sin\beta=\sin2\left(\dfrac\beta2\right)=2\sin\dfrac\beta2\cos\dfrac\beta2$

Let $x=\cos\dfrac\beta2$ and $y=\sin\dfrac\beta2$ . Then

$\begin{cases}\dfrac45=x^2-y^2\\\\\dfrac35=2xy\end{cases}\implies\begin{cases}\cos\dfrac\beta2=\dfrac3{\sqrt{10}}\\\\\sin\dfrac\beta2=\dfrac1{\sqrt{10}}\end{cases}$

from which we find

$\tan\dfrac\beta2=\dfrac{\sin\frac\beta2}{\cos\frac\beta2}=\dfrac13$

You can use the same ideas above to find the trig ratios for $\dfrac\alpha2$ , starting from the given fact that $\sin\alpha=\dfrac{16}{20}=\dfrac45$ .