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3 years ago

Can you please help me with an equation

Mathematics

1 answer:

kompoz [17]3 years ago

8 0

What’s the equation?

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Zoom in closely, pls help me

JulijaS [17]

Answer: a = 11.1

<u>Step-by-step explanation:</u>

a(0.3 - y) + 1.1 + 2.4x = 0

Let y = 1.3 → a(0.3 - 1.3) + 1.1 + 2.4x = 0 → -a + 1.1 + 2.4x = 0 → a = 1.1 + 2.4x

(y - 1.2) = -1.2(x - 0.5)

Let y = 1.3 → (1.3 - 1.2) = -1.2(x - 0.5) → 0.1 = -1.2x + 0.6 → -0.5 = -1.2x → $\dfrac{50}{12}=x\ \rightarrow\ \dfrac{25}{6}=x$

a = 1.1 + 2.4x

$=1.1+2.4\bigg(\dfrac{25}{6}\bigg)$

= 1.1 + 0.4(25)

= 1.1 + 10

= 11.1

5 0

3 years ago

Select the reason why these triangles are

Brut [27]

AA because the angles are the same but the sides are not

3 0

2 years ago

A seamstress makes 2 cushions for a couch, a smaller cushion and a larger cushion. The cushions are similar rectangular prisms.

Allisa [31]

Do you need help or you just wanted the answer?

5 0

2 years ago

List the side lengths of XYZ in order from smallest to largest<br><br> _ < _ < _

Alina [70]

Answer:

XZ<ZY<XY

Step-by-step explanation:

smallest angles are across from the smallest sides

I'm not 1000% sure I did this correct??? I hope this was right/it helped though

5 0

3 years ago

A cooler has a temperature of 32 degrees Fahrenheit. A bottled drink is placed in the cooler with an initial temperature of

FinnZ [79.3K]

Answer:

$k \approx 0.44$

Step-by-step explanation:

Given function:

$f(t) = (ce)^{-kt}+32$

As per question statement:

Initial temperature of bottle is 70 $^\circ F$ .

i.e. when time = 0 minutes, f(t) = 70 $^\circ F$

$70 = ce^{-k\times 0}+32\\\Rightarrow 38 = ce^{0}\\\Rightarrow c = 38$

After t = 3, f(t) = 42 $^\circ F$

$42 = 38 \times e^{-k\times 3}+32\\\Rightarrow 42-32 = 38 \times e^{-3k} \\\Rightarrow 10 = 38 \times e^{-3k} \\\Rightarrow e^{3k} = \dfrac{38}{10}\\\Rightarrow e^{3k} = 3.8\\\\\text{Taking } log_e \text{both the sides:}\\\\\Rightarrow log_e {e^3k} = log_e {3.8}\\\Rightarrow 3k \times log_ee=log_e {3.8} (\because log_pq^r=r \times log_pq)\\\Rightarrow 3k \times 1=log_e {3.8}\\\Rightarrow 3k = 1.34\\\Rightarrow k = \dfrac{1.34}{3}\\\Rightarrow k \approx 0.44$

Hence, the value is:

$k \approx 0.44$

8 0

3 years ago