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ziro4ka [17]
3 years ago
5

Change to an improper fraction 4 2/3=

Mathematics
2 answers:
vivado [14]3 years ago
8 0
First multiply the denominator by the whole number.
3*4=12
Now add the numerator.
12+2=14
14 is the numerator,  denominator stays the same.
You answer is 14/3!
barxatty [35]3 years ago
4 0
Solutions 

To solve the problem the first step is to m<span>ultiply the whole number by the fraction's denominator (4 x 3).Add the numerator (2) to the product. 

4 * 3 = 12 

12 + 2 = 14 

= 14/3 </span>
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A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip
DochEvi [55]

Answer:

The expression that represents the population of elk is: \text{elk}(t) = 2*3^t. It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at \text{elk}(0) = 2, then after the first year the population will be:

\text{elk}(1) = \text{elk}(0)*3 = 2*3

While on the second year, it'll be:

\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2

On the third year:

\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3

And so on, therefore the expression that describes the population of elk as the years passes is:

\text{elk}(t) = 2*3^t

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6

The population will reach 1,458 elk in 6 years.

8 0
3 years ago
Grace and her brother need $400 to go to band camp. Their parents have agreed
Virty [35]

Answer:

R. 25m + 10b = 400

Step-by-step explanation:

25m: $25 for time the mow the lawn

10b: $10 for every hour that they babysit their younger brother

400: They need $400 in total

+ : You need to add what they made for mowing the lawn and for babysitting.

6 0
3 years ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving
zhuklara [117]

Answer:

Answer D:  12

Step-by-step explanation:

Three distinct denominators are shown here:  4, 3 and 2.  The LCD is 12.

This corresponds to answer D.

4 0
3 years ago
Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
3 years ago
What fraction is equivalent to 12/48
Rashid [163]
The answer is 1/4.....
8 0
3 years ago
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