What fraction is equivalent to 12/48

Find the area of the triangle. Round the answer to the nearest tenth. Triangle is SSA. a= 3.7 b= 3.7 β= 70° ----- A.4.4 square u

Alexus [3.1K]

Answer:

A. 4.40 square units

Step-by-step explanation:

The triangle is isosceles with base angles of 70°. The a.pex angle will be ...

180° -2(70°) = 40°

The area of a triangle can be computed from two sides and the angle between them as ...

A = (1/2)ab·sin(γ)

A = (1/2)(3.7)(3.7)sin(40°) ≈ 4.40 . . . square units

3 0

3 years ago

X=5 y = 3, x² + 3(x +y)=<br> HELP FAST

umka2103 [35]

9514 1404 393

Answer:

49

Step-by-step explanation:

Put the variable values in place of the corresponding variables, and do the arithmetic.

x² +3(x +y) =

5² +3(5 +3) = 25 +3(8) = 25 +24 = 49

5 0

3 years ago

Leslie is a biologist. She is going to randomly select one animal from her lab to study. There are 5 salamanders, 3 crayfish, an

Scrat [10]

5/20 but if you were to simplify it then 1/4

8 0

3 years ago

Read 2 more answers

A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const

Ludmilka [50]

Answer:

$0.609 \leq \sigma \leq 0.772$

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation

s=0.68 represent the sample standard deviation

$\bar x =98.90$ represent the sample mean

n=98 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=98-1=97$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.