Answer:
After 1 second, the ball will reach a maximum height of 16 feet
Step-by-step explanation:
The height of the ball after t seconds: h(t) = -16t^2 + 32t
The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola
t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second
then
h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16
After 1 second, the ball will reach a maximum height of 16 feet
Answer:
456/7 equal to (drum rolls) 65.1428571429
Step-by-step explanation:
Answer:
length = 115 cm
width = 108 cm
Step-by-step explanation:
The perimeter of a rectangular swimming pool is 446 centimeters
LEt L be the length of the pool
The width of the pool is 7 centimeters less than the length of the pool.
width = length - 7
W= L-7
Given perimeter = 446
Perimeter of rectangle = 2(length)+2(width)
446 = 2(L) + 2(W) we know W = L-7
446 = 2(L) + 2(L-7)
446 = 2L + 2L - 14
Add 14 on both sides
460 = 4L
divide by 4 on both sides
L= 115
Length L= 115
Width W = L - 7 = 115 - 7= 108
The simplification of the given algebraic expression is;
yz = (z + 1)/z(z - 1)
<h3>How to simplify algebraic expressions?</h3>
We are given y left parenthesis z right parenthesis which is expressed as; yz
Now, we are given the algebraic expression that yz equals space fraction numerator z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction
z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction is expressed as; (z² - 1)/z(z - 1)²
Thus, our main expression is;
yz = (z² - 1)/z(z - 1)²
Factorizing the numerator and denominator gives;
yz = (z + 1)(z - 1)/z(z - 1)(z - 1)
(z - 1) is common to both numerator and denominator and as such, we now have;
yz = (z + 1)/z(z - 1)
Read more about Algebraic Expressions at; brainly.com/question/4344214
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1) <span>Enter the missing numeral of the answer 1, 3. Use a number only.
2) </span>f(x) = x^2 - 5x - 6 can be written as <span>f(x) = x^2 - 5x - 6 = (x-1) (x+6)
the zeros are 1 and 6, and the smallest zero is 1,
3) </span>g(x) = x^2 - 8x =<span>g(x) = x(x - 8), so the zeros are 0 and 8, the smallest zero is 0
4) </span>f(x) = x^2 - 7x + 6 can be written as <span>f(x) = x^2 - 7x + 6 = (x-1) (x-6), the zeros are 1 and -6, and the smallest zero is 1
5) </span>g(x) = x^2- 6x - 16 can be written as <span>g(x) = x^2- 6x - 16 = (x+2) (x-8)
the zeros are -2 and 8, the smallest zero is -2</span>
