The angle that is obtuse is 1, because it is greater than 90°.
Hope this helps and have a nice day:)
The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation

This gives

Evaluate the products

Evaluate the like terms

So, we have
f(x) = x²+ 2/3x - 1/9
Read more about quadratic equations at
brainly.com/question/1214333
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Answer:
x = 26
y = 9
Step-by-step explanation:
(5x - 17)° + (3x - 11)° = 180° (angles in a straight line)
Solve for x
5x - 17 + 3x - 11 = 180
Collect like terms
5x + 3x - 17 - 11 = 180
8x - 28 = 180
Add 28 to both sides
8x = 180 + 28
8x = 208
Divide both sides by 8
x = 208/8
x = 26
Also:
(2y + 5)° + 90° + (3x - 11)° = 180° (angles on a straight line)
Plug in the value of x and solve for y
2y + 5 + 90 + 3(26) - 11 = 180
2y + 5 + 90 + 78 - 11 = 180
Collect like terms
2y + 162 = 180
Subtract 162 from both sides
2y = 180 - 162
2y = 18
y = 9 (dividing both sides by 2)


- A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
- B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
- C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
- D) 70/100 + 3/10 = <u>1</u>
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<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>
For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "
" and "3". The
term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as
using the zero exponent rule.
The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.