Answer:
D.) You can show your name printed on the team roster.Step-by-step explanation:
Answer:
It's below in the explanation
Explanation
1. x has to be greater than 2. So 3 and 4 both work
2. x has to be less than 22. So 21 and 20 both work
3. t has to be less than 5. So 3 and 4 both work
4. There isn't a number there. what is 5 less that?
5. j has to be less than 5 so 5 and 4 both work
6. y has to be less than 4. So 4 and 3 both work
7. B has to be greater than 26. so 26 27 and 28 all work
8.There isn't a number there
9.b can be 3 or greater than 3.
10.z can be 6 or greater than 6
Hope this Helps!
Answer:
13/14
Step-by-step explanation:
The GCF between 26 and 48 is 2. So divide 26/2=12 and 48/2=13 13/14. And after that you can not simplify anymore so 13/14 is 26/48 in it's simplest form.
Hope it helps!
Answer:
True
Step-by-step explanation:
The sum of measures of these three angles of any triangle is invariably equal to the straight angle, also expressed as 180 °.
24+30+126=180
The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
