The air force plane travelled for a total of 6.9 hours.
<u>SOLUTION:
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Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.
We have to find the number of hours the Air Force plane flew before the cargo plane caught up.
Now, we know that,
For air force plane
Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.
So,
Time taken by air force plane = 6.9 hrs
Answer:
20%
Step-by-step explanation:
1/5 of 1 hour = 20 minutes
so 1/5 = 20%
25% + 20% = 45%
0.35 = 35%
45% + 35% = 80%
100% - 80% = 20%
Answer = 20%
Hope this helps!
Answer:
No.
Step-by-step explanation:
For there to be a equal sign, it will mean that both sides will have to have the same exact amount. If it is expressions on both sides, then the expressions must, when combined, equal to each other.
In this case, there is not given operation that will allow for both numbers to equal each other, and 17.8 is 10 less than 18.8, therefore it is not reasonable.
17.8 ≠ 18.8
Photomath is good for this type of thing