Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Answer:
sorry I dont know the way u put it makes no sense
Answer:
The first one is ur answer
Step-by-step explanation:
Answer: plane A = 333.33mph
Plane B = 500mph
Step-by-step explanation:
Given data:
Distance between the two planes = 2400miles.
Plane A flew North
Plane B flew south
Solution:
Let v represent plane A.
Let 2v represent plane B.
Distance between the two plane
v + 1.5* v = 3*v
7.5v = 2500miles
v = 333.33mph
Plane B has one and half times the speed of plane A
= 1.5 * 333.33
= 500mph
