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2 years ago

Find the measure of angle 1, 2, 5 and 6. Show your work! 3 4 1 2 5 6 68

Mathematics

1 answer:

Andre45 [30]2 years ago

6 0

Sorry but where is the picture? I’m confused..

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If u help me then i will love you forever

Darina [25.2K]

ok what do u need help with I don't see anything

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3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

What is 14x14x14 equal

N76 [4]

2744 is the answer. can be written as 14^3 just in case you need to know that.

8 0

2 years ago

In a group of 33 high school students, 10 take French, 11 take Spanish, and 5 take both languages. How many students of group ta

lilavasa [31]

Answer:

Step-by-step explanation:

Add 10,11, and 5

10+11+5=26

subtract 26 from 33

33-26=7

6 0

2 years ago

The quotient of twice a number t and 12

Arisa [49]

(t + 12) ^ 2
(t + 12) (t + 12)
t ^ 2 + 12t + 12t + 144 144 24
t ^ 2 + 24t + 144 -------|--------
(t + 12) (t + 12) = 0 12,12 | 24

t = -12

5 0

3 years ago