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Step2247 [10]
3 years ago
7

The table shows the relationship between the number of faculty members and the number of students at a local school. What is the

missing value?
Faculty
Students
1
17
2
34
3
51
4
?
17
68
85
102
Mathematics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

ITS C I DID THE TEST TRUST ME

Step-by-step explanation:

have nice day god bless u and im pretty sure this is the answer if not then its b

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A line segment has endpoints (-5, 10) and (a,b) . If the midpoint of the segment is (13, -2), what is the absolute difference be
AlexFokin [52]
If the line segment point is D(-5, 10) and E(a,b) and the  midpoint of the segment is F(13, -2) that mean 
DE= 2*DF

You can directly find the distance of AC 
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12

Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf 
a= -5 +2*18= 31

Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14

<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
7 0
3 years ago
Question content area top
Dahasolnce [82]

Answer:

695

Step-by-step explanation:

6 0
2 years ago
Ms. Lynch has 21 coins in nickels and dimes.
bulgar [2K]

Answer:

Step-by-step explanation:So we know x + y = 21 and 5x +10y = 165 We line them up in columns    x +   y =   21  5x +10y = 165 To eliminate the x variable, I'll multiply every element in the 1st equation by -5. -5x + -5y = -105  5x + 10y =  165 Now we combine (add) the equations, which eliminates x altogether.  5y = 60   ...   y = 12 From there, x + 12 = 21  ...  x = 21-12  ...  x = 9 You should double check.  Do 9 nickles and 12 dimes equal $1.65? A very important thing to remember using this method is to do the same thing to each element in the equation that you change! I hope that helps.

4 0
2 years ago
The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter
CaHeK987 [17]
X - a leg  (x > 6);
x - 6 - a leg;
x + 1 - a <span>hypotenuse;</span>
Use the Pythagorean theorem
(x+1)^2=x^2+(x-6)^2

Use:(a\pm b)^2=a^2\pm2ab+b^2

x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}

x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}

The perimeter:

7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}
5 0
3 years ago
Here's a graph of a linear function. Write the
Anastaziya [24]

Answer:

y=2x-4

Step-by-step explanation:

8 0
3 years ago
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