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3 years ago

7

The table shows the relationship between the number of faculty members and the number of students at a local school. What is the

missing value?
Faculty
Students
1
17
2
34
3
51
4
?
17
68
85
102

1 answer:

Mrac [35]3 years ago

8 0

Answer:

ITS C I DID THE TEST TRUST ME

Step-by-step explanation:

have nice day god bless u and im pretty sure this is the answer if not then its b

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If f (x)=3^5-x + 6, what is the value of f (5), to the nearest tenth?

Amiraneli [1.4K]

Answer:

240

Step-by-step explanation:

3^5 - 5 + 6

243 - 5 = 238+6= 244

240?

8 0

3 years ago

Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

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11 months ago

Please help! I mark brainliest :3

vladimir1956 [14]

no for a
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2 years ago

A coin is flipped twice. What is the probability that the coin will land on tails on the first flip and will land on tails again

bixtya [17]

Answer:

1/4=0.25=25%

Step-by-step explanation:

A coin has two sides, heads and tails, and if you take 100% divided by two you get 50, you want to know what is the probability it will land on tails TWICE so divide 50 by two and you get 25.

1/2=50

1/4=25

0.25 x 100= 25%

hope that helps

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2 years ago

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Find the complementary angles of the following.

vovikov84 [41]

Answer:

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B24

C93

D47

E 31

F 48

2. 160

A10

B20

C30

D40

E 50

F 60

3. 68

A851

B295

C302

D574

E 112

F 638

4. 174

A3

B4

C5

D 6

E 7

F 8

5. a

A180-a

B180/2

C 179*a

D 179+a

E 60

F pi

Find the complementary angles of the following.

6. 53

A90

B32

C 25

D 45

E 18

F 37

7. 12

A46

B78

C98

D31

E 52

F 64

8. 73.5

A16.5

B34.2

C29.4

D17.7

E 57.9

F 11.3

9. 23.7

A66.3

B70.1

C42.5

D83.9

E 54.8

F 36.2

10. a

A90/a

Ba-90

Ca/2

D90-a

E 90-2

F a^2

Two of the angles are listed. Find the measure of the third angle in each triangle. Similar to example 6

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A23

B42

C47

D60

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F 89

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B34

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A15

B90

C29

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B112 - 7a

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F 302 - 1a

19. x, (x + 20)

A189 - 7x

B167 - 1x

C114 - 5x

D160 - 2x

E 124 - 2x

F 142 - 1x

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2. B

3. E

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6. F

7. B

8. A

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10. B

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13. D

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19. D

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Step-by-step explanation:

6 0

3 years ago