Find zeros of x^4-5x^2+4

Find the size of angle XYZ. Give your answer to 1 decimal place. Z 13 cm x Y 4 cm

Rzqust [24]

Answer:

solution,

 $tan \: y \: = \frac{13}{4} \\ y = {tan}^{ - 1} ( \frac{13}{4} ) \\ y = 72.9$ 

hope this helps ....

Good luck on your assignment...

7 0

3 years ago

Read 2 more answers

PLEASE PLEASE PLEASSE HELP I WILL MARK BRAINLIEST!!! FIRST TO GIVE A PROPER ANSWER WILL GET BRAINLIEST

juin [17]

Answer:

Answer to 9 is B answer to 10 is C

Step-by-step explanation:

Please give brainliest

7 0

3 years ago

What is the mode of these numbers: 10, 13, 800, 24 and 13

OverLord2011 [107]

A mode is the number that appears the most in a set of numbers. (I'm going to put the numbers in order before I solve this)

10, 13, 13, 24, 800

The answer is 13, because it appears more than any of the other numbers. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)

3 0

3 years ago

Read 2 more answers

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun

AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

Nonsmokers Light Smoker Heavy smoker Total

Men 303 35 37 375

Women 413 31 45 489

Total 716 66 82 864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

$82C2=\frac{82!}{2!(82-2)!}=3321$

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

$864C2=\frac{864!}{2!(864-2)!}=372816$

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

$P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908$

4 0

3 years ago