Answer:
A shaded region below a dashed line (y <3x-4)
Step-by-step explanation:
For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.
Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.
In this case what we have here is an open region, as the graph below shows.
3x-y>4 =-y>4-3x∴y<3x-4
Setting a value for x
3x-4=0
3x=4
3x/3=4/3
x=4/3 (slope)
(4/3,0)
Answer:
12*56-56+11=12
Step-by-step explanation:
12 for 56
So assuming simplet interest
find the change to find the interest
change=186000-129000=57000
simple interest=time times rate times principal
time is in years (8)
rate is in decimal
principal is amount invested (129000)
so
interest is 57000
57000=(8)(r)(129000)
57000=1032000r
divide both sides by 1032000
0.05523255813953488372093023255814=r
or
5.523255813953488372093023255814%
rounded
5.5%
Answer:
$23.54
Step-by-step explanation:
12.95+2.76+7.83=23.54
Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
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