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2 years ago

(3n4 + 6n + 6n)– (n+4n4 + 7n)

Mathematics

2 answers:

scZoUnD [109]2 years ago

8 0

3n4+12n-n-4n4-7n
3n4-4n4=-1n4
12n-7n-n=4n
The answer will be
-1n4+4n

Oksi-84 [34.3K]2 years ago

7 0

Answer:

-n⁴ + 4n

Step-by-step explanation:

Step 1: Write expression

(3n⁴ + 6n + 6n) - (n + 4n⁴ + 7n)

Step 2: Combine like terms

3n⁴ + 12n - (4n⁴ + 8n)

Step 3: Distribute -1

3n⁴ + 12n - 4n⁴ - 8n

Step 4: Combine like terms

-n⁴ + 4n

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Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

2 years ago

For a and b, write an equation in slope-intercept form that meets the given criteria

MariettaO [177]

Answer:

A) y = -2x

B) y = x - 3

Step-by-step explanation:

A) you need to have a negative 'x' coefficient and no y-intercept

B) you need to have a positive 'x' coefficient and a negative y-intercept

8 0

1 year ago

Which two values of x are roots of the polynomial below?<br><br> x^2 + 5x + 9

4vir4ik [10]

$x^2+5x+9$

The polynomial cannot be factored with rational numbers due to b being 5. You can factor it if b is equal to 6.

None

5 0

2 years ago

Read 2 more answers

If p is the incenter of triangle jkl, find each measure

Hunter-Best [27]

Answer:

PO = 7

PM = 7

MJ = 11

∠PJO = 32°

∠KJL = 64°

PL ≈ 18.385

OL = 17

∠PLO = 22°

∠NLO = 44°

∠JKL = 72°

∠MKP = 36°

∠NKP = 36°

∠PKN = 36°

KN = 10

PL ≈ 13.04

PK ≈ 12.21

JL = 28

JK = 21

LK = 27

Step-by-step explanation:

The given parameters are;

The point representing the incenter of the triangle = P

Therefore PO = PM = PN = 7

tan(32°) = PM/JM = 7/JM

∴JM = 7/(tan(32°)) ≈ 11.2

∠PJO = tan⁻¹(7/11)≈ 32.47°

∠PJO = ∠PJM = 32° similar triangles

∠KJL = ∠KJP + ∠PJO = 32 + 32 = 64°

∠KJL ≈ 64°

PL = √(7² + 17²) ≈ 18.385

OL = NL = 17 similar triangles

∠PLO = sin⁻¹(7/18.385) ≈ 22.380°

∠PLO = ∠PLN = 22°

∠NLO = ∠PNL + ∠OLP ≈ 22° + 22° ≈ 44°

∠NLO ≈ 44.380°

∠JKL = 180 - (∠KJL + ∠NLO)

∠JKL = 180° - (64° + 44°) ≈ 72°

∠JKL ≈ 72°

∠MKP = ∠NKP = 72°/2 = 36°

∠MKP = 36°

∠NKP = 36°

∠PKN = ∠JKL - ∠MKP = 72° - 36° ≈ 36°

∠PKN ≈ 36°

KN = KM = 10

MJ = OJ = 11

PL = √(7² + 11²) ≈ 13.04

PK = √(7² + 10²) ≈ 12.21

JL = JO + OL = 11 + 17 = 28

JK = JM + MK = 11 + 10 = 21

LK = LN + NK = 17 + 10 = 27

6 0

1 year ago

Three ounces of broiled ground beef contains 245 calories. Is this the number of calories directly or inversely proportional to

aalyn [17]

Answer:

The number of calories are directly proportional to the number of ounces.

Step-by-step explanation:

We can relate these values as:

Let x be the calories in 4 ounces of broiled hamburger.

$\frac{3}{245} =\frac{4}{x}$

=> $3x=4\times245$

=> $3x=980$

Dividing by 3 on both sides;

x = 327 approx

We can see that 4 ounces contain 327 calories.

Per ounce will have $327/4=81.75$ calories.

As the quantity of hamburger increases, the calories count also increases.

8 0

3 years ago