Question

A bag holds 6 green, 9 red and 4 blue marbles a marble is selected at random what is the probability of not selecting a red marble?

Answer 1

Answer:

The probability of not selecting a red marble, P(R)'  = 10/19

Step-by-step explanation:

The probability of an event occurring is equal to the number of ways the required event occurs divided by the number of possible outcomes

The number of ways of an event not occurring is 1 less the probability of the event occurring

The number of green marbles in the bag = 6

The number of red marbles in the bag = 9

The number of blue marbles in the bag = 4

The sum of the marbles in the bag, n = 6 + 9 + 4 = 19

The number of ways of selecting a red marble = 9 ways

The probability of selecting a red marble = 9 ways/19 marbles = 9/19

The probability of not selecting a red marble = 1 - 9/19 = 10/19 = $0.\overline{526315789473684210}$

The probability of not selecting a red marble P(R)' = 10/19

Answer 2

Answer:

The probability of NOT selecting a red marble is 10/19 (or 52.6%)

Step-by-step explanation:

6 green+ 9 red+ 4 blue = 19 marbles in total. So 19 would be our denominator. The total of marbles that IS NOT red is 10 total (6+4). Now we would put 10 as our numerator. 10/19. We could simplify but 10 and 19 have no common factors. So it would but stay 10/19. Hope this helped