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mafiozo [28]
3 years ago
13

PLEASE HELP ME

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• tanx = \frac{sinx}{cosx}

• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Consider the left side

\frac{tan^2x-sin^2x}{tan^2x}

= \frac{tan^2x}{tan^2x} - \frac{sin^2x}{tan^2x}

= 1 - cos²x

= sin²x = right side ⇒ verified


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if we take 25 to be the 100%, what is 7 off of if in percentage?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 25&100\\ 7&x \end{array}\implies \cfrac{25}{7}=\cfrac{100}{x}\implies 25x=700\implies x=\cfrac{700}{25}\implies x=28

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3 years ago
Herman and Jackie are saving money to pay for college. Herman currently has $15,000 and is working hard to save $1000 per month.
Mashutka [201]

Answer:

Part 1) 10\ months

Part 2) \$25,000

Step-by-step explanation:

Let

y ----> the total amount of savings

x ----> the number of months

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

<em>Herman</em>

The slope is equal to m=\$1,000\ per\ month

The y-intercept is b=\$15,000

substitute

y=1,000x+15,000 ----> equation A

<em>Jackie</em>

The slope is equal to m=\$1,300\ per\ month

The y-intercept is b=\$12,000

substitute

y=1,300x+12,000 ----> equation B

Part 1) In how many months will they have the same amount of savings?

equate equation A and equation B

1,300x+12,000=1,000x+15,000

solve for x

1,300x-1,000x=15,000-12,000

300x=3,000

x=10\ months

Part 2) How much will each of them have saved?

substitute the value of x=10 months in any of the equations

equation A

y=1,000(10)+15,000=\$25,000

equation B

y=1,300(10)+12,000=\$25,000

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3 years ago
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Answer:

17 and 19

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18

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Answer:

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Step-by-step explanation:

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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