Question

PLEASE HELP ME

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• tanx = $\frac{sinx}{cosx}$

• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Consider the left side

$\frac{tan^2x-sin^2x}{tan^2x}$

= $\frac{tan^2x}{tan^2x}$ - $\frac{sin^2x}{tan^2x}$

= 1 - cos²x

= sin²x = right side ⇒ verified