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3 years ago

Identify the slope and y-intercept of y=-5x

Mathematics

1 answer:

Alika [10]3 years ago

4 0

The slope is 5.
And the y-intercept is 0.

Hope I helped! <3

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Fidn the points of intersection

Sedbober [7]

EQ. 1: x + y = 8

EQ. 2: 4x-y = 7

Rewrite EQ. 1 as EQ. 3: x = 8-y

Replace x in EQ.2 with EQ. 3:

4(8-y) - y = 7

Use the distributive property:

32 - 4y - y = 7

Combine like terms:

32 - 5y = 7

Subtract 32 from each side:

-5y = -25

Divide both sides by -5

y = -25 / -5

y = 5

Now replace y with 5 in EQ. 3 to solve for X:

x = 8-5

x = 3

The point of intersection is X = 3, Y = 5, which is written as (3,5)

8 0

3 years ago

Help please quickly thank you so much

STALIN [3.7K]

Answer:

120 deg

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$