1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
topjm [15]
3 years ago
8

You can convert temperature given in degrees Celsius to a Fahrenheit temperature by using the expression 9x / 5+ 32 , where x is

the celsius temperature .
a) Water freezes when the temperature is 0 degree C . At what Fahrenheit temperature does water freeze ?



b)Water boils at 100 degree Celsius . At what temperature does water boil in degrees Fahrenheit ?


c) The temperature of some water is 15 degree Celsius . What is the Fahrenheit temperature ?
Mathematics
1 answer:
andriy [413]3 years ago
4 0
The formula given in the question for conversion of temperature is

F = 9x/5 + 32
a. When temperature = 0 degrees centigrade, then
F = (9 * 0)/5 + 32
   = 0 + 32
   = 32 degree Fahrenheit

b when temperature of boiling water = 100 degree Celsius, then
F = (9 * 100)/ 5 + 32
   = 900/5 + 32
   = 212 degree Fahrenheit

c. When temperature of water is 15 degree Celsius, then
F = (9 * 15)/5 + 32
   = 27 + 32
   = 59 degree Fahrenheit


You might be interested in
What is the solution for 5x^2-x+6=0
kati45 [8]

The easiest way to solve this problem is by using the Pythagorean theorem :D

Pythagorean theorem: [-b +- sqrt(b^2 - 4ac)]/2a

5 = a

-1 = b

6 = c

therefore, by plugging these values in!

[-(-1) +- sqrt((-1)^2 - 4(5)(6))]/2(5)

[1 +- sqrt(1 - 120)]/10

Oh so we're using imaginary numbers, so in this case you'll need to know that i = sqrt(-1), so keep this in mind (I can see why this was so difficult)

[1 +- sqrt(119)*i]10

answers:

( 1 + i*sqrt(119) ) / 10

( 1 - i*sqrt(119) ) / 10

7 0
3 years ago
Finding the area of a regular polygon​
ddd [48]
<h2><u>Solu</u><u>tion</u><u>:</u></h2>

360° ÷ 10 ÷ 2 = 18°

So the length of the decagon side is:

10 × tan18° × 2 = 20 × tan18°

The area is: ½ × 20 × tan18° × 10 × 10 = 1000 × tan18°

≈ 324.9

.: <u>3</u><u>2</u><u>4</u><u>.</u><u>9</u> is the final answer.

<em>I</em><em> </em><em>h</em><em>ope</em><em> </em><em>this</em><em> helps</em><em>. </em>

5 0
2 years ago
What is the simplified expression for –3cd – d(2c – 4) – 4d?
kompoz [17]
<span>–3cd – d(2c – 4) – 4d
= </span><span>–3cd – 2cd + 4d – 4d
= -5cd

answer
</span><span>A:–5cd </span>
3 0
3 years ago
Determain the equation, in slope intercept form, of the line of the line that has a slope of -6 and passes through the point P(-
Vinil7 [7]

Answer:

<h2>         y = -6x - 16</h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -6

(-3, 2)    ⇒   x₀ = -3,  y₀ = 2

The point-slope form of the equation:

y - 2 = -6(x + 3)

So:

y - 2 = -6x - 18         {add 2 to both sides}

y = -6x - 16             ←  the slope-intercept form of the equation

5 0
3 years ago
What is: <br> 8x - 2(4 + 3x)
Angelina_Jolie [31]
8x-2(4+3x) =0\\ 8x-8-6x=0 \\ 2x-8=0 \\ 2x=8 \\ x=4
6 0
3 years ago
Read 2 more answers
Other questions:
  • Bridget opened 5,000 as shown. Use your understanding of place value to explain how the ungrouped number is equal to 5,000.
    15·1 answer
  • Help plzzzz ASAPPPPP
    9·1 answer
  • -13=5(1+4x)-2x<br> With steps
    14·2 answers
  • Do y’all the answer?
    12·1 answer
  • How to identify the independent and dependent variable?
    5·1 answer
  • Just need help on first one.​
    12·1 answer
  • M=-9 and goes through (3,4)
    11·1 answer
  • Classify this triangle by its sides.
    12·1 answer
  • The average number of passes in a football game is right skewed with mean 75 and variance 961. If we sample 100 random games, wh
    8·1 answer
  • A single, standard cube is tossed. What is the probability of getting a number greater than 3?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!