F(x) = x² - 10x + 24
opens up because coefficient of x² is positive
crosses x-axis at x = 6 and x = 4
crosses y-axis at y = 24
vertex is a minimum at (5, -1)
Logarithm base 8 of 8 is 1 .
A) h(x)+g(x)=(3x-4)+<span>(9x+1)=12x-3
B) </span>g(x) + f(x)=(9x+1)+<span>(7x+2)=16x+3
C) g(x)*h(x)= (9x+1)(3x-4)=27x²+3x-36x-4=27x²-33x-4
D)h(x)-g(x)=(3x-4)-(9x+1)= - 6x -5
if f(x)= -7x +2
B) g(x)+f(x)=(9x+1)+(-7x+2)=9x-7x+1+2=2x+3
answer B</span>
Question 1:
Since the diagonal is an angle bisector for both opposite angles and each set of opposite sides are parallel, this shape is a rhombus.
Question 2:
Since this is a rectangle, the diagonals are equal. Thus, each half of the diagonal must be equal to each other as well.
5x - 5 = 3x + 3
Subtract both sides by 3x
2x - 5 = 3
Add both sides by 5
2x = 8
Divide both sides by 2
x = 4
Have an awesome day! :)