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3 years ago

The figure below shows the correct construction of a segment bisector.

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

it's false.... not sure

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Write three numbers greater than 20 that have 9 as a factor

Lubov Fominskaja [6]

We just need to find the multiples of 9 that are greater than 20.

9*1 = 9
9*2 = 18
9*3 = 27
9*4 = 36
9*5 = 45

We can use 27,36, 45, .....
Your final answer should be any multiple of nine greater than 20. I recommend using 27, 36, and 45. Hope this helps!<span />

6 0

2 years ago

Pls answer my other question before this one. i need dem smart people and if you want to answer the qeustion on this one the her

lozanna [386]

Answer:

do you still need this answer to this question and where is the other question??

Step-by-step explanation:

4 0

2 years ago

The rent for an office space is $674.30 per month. The office is 306 1/2 square feet in area.What is the monthly cost per square

Rufina [12.5K]

The answer is B because 674.30 divided by 306.5 equals 2.2 or $2.20

3 0

3 years ago

Draw a pair of supplementary adjacent angles. One of the angles should have a measure of 85 degrees. How should the supplementar

Orlov [11]

Supplementary adjacent angles form a "linear pair." Together, they make a line. The angle supplementary to 85° will be slightly obtuse, just as 85° is slightly acute.

4 0

2 years ago

Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8

vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function $f(x)=1/x$ . We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b} =-1/8$

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

$\frac{.5b-1}{2b-b^2} =\frac{-1}{8}$

Now, cross multiply.

$4b-8=b^2-2b$

$b^2-6b+8=0$

Solve for b. Factor using the numbers -4 and -2.

$=(b-4)(b-2)=0$

Thus, b=4 or b=2.

However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.

4 0

2 years ago