3 years ago

The figure below shows the correct construction of a segment bisector.

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

it's false.... not sure

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sweet [91]

Submit anwser it’s correct can i get brainliest

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3 years ago

I WILL MARK AS BRAINLIEST!!! What is the value of x?<br><br> 8x+3=43

uysha [10]

8x+3=43
-3 -3
8x=40
/8 /8
X=5

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3 years ago

Marcia will make a frame for her picture the length of the picture is 15 inches the width is one third of the length how much wo

vovangra [49]

The answer to that would be 5 !!!!

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3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

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3 years ago

What is the scale factor when a larger image Q has an area of 36 square units and the smaller version has an area of 9 square un

schepotkina [342]

Answer:

Step-by-step explanation:

scale factor means the amount of times you need to multiply

so,

36/9

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2 years ago