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egoroff_w [7]
3 years ago
12

Write 2^-3=1/8 in logarithmic form

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

That is your answer if it is wrong i will try to fix it

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Factor completely 3bx2 − 9x3 − b + 3x. (b − 3x)(3x2 − 1) (b + 3x)(3x2 + 1) (b + 3x)(3x2 − 1) Prime
Daniel [21]
3bx^2-9x^3-b+3x=\boxed{3x^2}\cdot b-\boxed{3x^2}\cdot3x\fbox{-1}\cdot b\fbox{-1}\cdot (-3x)\\\\=\boxed{3x^2}(b-3x)\fbox{-1}(b-3x)=\boxed{(b-3x)(3x^2-1)}\\\\completely:\\use:a^2-b^2=(a-b)(a+b)\to3x^2-1=(x\sqrt3)^2-1^2=(x\sqrt3-1)(x\sqrt3+1)
therefore:\\3bx^2-9x^3-b+3x=(b-3x)(3x^2-1)\\=\underline{\underline{(b-3x)(x\sqrt3-1)(x\sqrt3+1)}}
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3 years ago
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Find the equation of the graphed line and select the best answer from the choices provided.​
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HELP A NGA OUTtt!!!!QUickkkkk
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اكتشف بنفسك أيها الغبي :)
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