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Stella [2.4K]
3 years ago
7

Someone, please explain I am so confused 20 POINTS

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0
The answer is 12 r of 4
velikii [3]3 years ago
4 0

Answer:

it would be 64 divided by 5 equal 12 R 4

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Solve this equation.
Anika [276]

Answer:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal

Step-by-step explanation:

Solve for b:

b - (3 + 2/5) = 8 + 1/5

Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:

b - (5×3)/5 + 2/5 = 8 + 1/5

5×3 = 15:

b - (15/5 + 2/5) = 8 + 1/5

15/5 + 2/5 = (15 + 2)/5:

b - (15 + 2)/5 = 8 + 1/5

15 + 2 = 17:

b - 17/5 = 8 + 1/5

Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:

(5 b)/5 - 17/5 = 8 + 1/5

(5 b)/5 - 17/5 = (5 b - 17)/5:

(5 b - 17)/5 = 8 + 1/5

Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:

(5 b - 17)/5 = (5×8)/5 + 1/5

5×8 = 40:

(5 b - 17)/5 = 40/5 + 1/5

40/5 + 1/5 = (40 + 1)/5:

(5 b - 17)/5 = (40 + 1)/5

40 + 1 = 41:

(5 b - 17)/5 = 41/5

Multiply both sides of (5 b - 17)/5 = 41/5 by 5:

(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 41

Add 17 to both sides:

5 b + (17 - 17) = 17 + 41

17 - 17 = 0:

5 b = 41 + 17

41 + 17 = 58:

5 b = 58

Divide both sides of 5 b = 58 by 5:

(5 b)/5 = 58/5

5/5 = 1:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal


5 0
3 years ago
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify
irina [24]

Answer:

x-coordinates of relative extrema = \frac{-1}{2}

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}

Differentiate with respect to x

f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}

f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}

Differentiate f'(x) with respect to x

f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1

At x = \frac{-1}{2},

f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0

We know that if f''(a)>0 then x = a is a point of minima.

So, x=\frac{-1}{2} is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0
3 years ago
your teacher has 36 carpet squares. She needs to make a new arrangement for the reading carpet what are all of the different way
Simora [160]
3 rows of 12

9 rows of 4

2 rows of 18

6 rows of 6
6 0
3 years ago
The vertices of the triangle is A(-2,4), B(1,2), C(-2,-2)
spin [16.1K]
See description in the pic.

5 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLEST
nadya68 [22]

OK.  All the work is in the attached drawing.

Please spend enough time with it to understand what was done and how, so that you can do the next problem like this one completely on your own.

Good luck !

==============================

Here's a picky pickypoint to think about concerning the "cost".  I'm not quite sure what to do about this:

The initial, one-time $55 is a "deposit".  If she doesn't smash the bike or steal it, she gets the $55 back when she returns the bike.  

So if she eventually gets the $55 back, <u><em>is it a cost</em></u> ? ?  I don't know how to think about it.

She does need to <em>give</em> them the $55 at the beginning, just to take the bike out.  So she has to have it with her and give it to them temporarily, even though she'll  get it back, and she'll still have it when she returns home.

So here's the story:  

-- While she HAS the bike, the graph correctly shows all the money she needs, in order to get the bike, and keep it for however long she keeps it.

-- Finally, at the end of the week, after she returns the bike and gets her $55 back, the line and everything on the graph will shift down by $55.  The line will start at zero, and the little red ordered pairs will also shift straight down and still be on the line.

To put it one more way:

-- While Jen has the bike, the y-intercept of the graph is $55.

-- After she returns the bike in good condition, the y-intercept is zero.

6 0
3 years ago
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