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barxatty [35]
3 years ago
10

Mike and Larry are friends who share the same birthday.They decided to have a birthday party together and their friends. Mike re

ceived 21 gifts while Larry received 12 gifts. What is the ratio of gifts for Mike to Larry ​
Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0

Answer:

21:12

Step-by-step explanation:

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Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
How to find the exterior angle sum of a 500gon
seropon [69]
360 deegrees you welcome
6 0
3 years ago
What is the value of 5⁸
zimovet [89]

Answer:

390625

Step-by-step explanation:

5x5x5x5x5x5x5x5

6 0
3 years ago
Read 2 more answers
Use synthetic division to solve (2x^3+4x^2-35x+15) divided by (x-3) What is the quotient?
Salsk061 [2.6K]

Answer:


Step-by-step explanation:

The only thing you need to watch carefully is the divisor which in this case is   x - 3. The divisor, in synthetic division, is the number that will make the binomial go to 0.  

x - 3 =0

x = 3

So the divisor is 3.

3  ||  2    4    -35    15

             6     30    -15

======================

       2   10    -5      0

So the quotient is

2x^2 + 10x - 5 with no remainder


7 0
3 years ago
Read 2 more answers
Which of the following is true about an isosceles trapezoid?
mixas84 [53]
<span>The diagonals are congruent.

</span>
6 0
3 years ago
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