Answer: 3.6
Step-by-step explanation: 3x1.2= 3.6
Answer:
yes
Step-by-step explanation:
Answer:
<u>First figure:</u> 
<u>Second figure:</u> 
<u>Third figure:</u>
- Height= q
- Side length = r
<u>Fourth figure: </u> 
Explanation:
<u></u>
<u>A. First figure:</u>
<u>1. Formula:</u>

<u>2. Data:</u>
<u>3. Substitute in the formula and compute:</u>

<u>B. Second figure</u>
<u>1. Formula: </u>

<u>2. Data:</u>
<u>3. Substitute and compute:</u>

<u></u>
<u>C) Third figure</u>
a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.
When the base of the pyramid is a square the four edges of the base have the same side length.
<u>D) Fourth figure</u>
<u>1. Formula</u>
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

<u>2. Data: </u>
- side length of the base: 11 cm
<u>3. Calculations</u>
a) <u>Calculate the area of the base</u>.
The base is a square of side length equal to 11 cm:

b) <u>Volume of the pyramid</u>:

The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
With what? i dont see the picture
Step-by-step explanation: