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3 years ago

A nurse has a gross income of $1200. And net income of $950 per week. What is the percentage deductions per week

Mathematics

1 answer:

denpristay [2]3 years ago

7 0

1200 - 950 = 250

250/1200 = 0.2083 = 20.8% in deductions

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meg has $20 in a savings account that earns 10% annually. the interest is not compounded. how much will she have in 1 year

snow_tiger [21]

<h2>Answer: 22$</h2>

Step-by-step explanation: 10% of 20 is 2 so 20 + 2 = 22.

Hope this helps! ;)

4 0

3 years ago

Given: △FKL, FK= a<br> m∠F=45°, m∠L=30°<br> Find: FL

mr Goodwill [35]

The sum of angles of a triangle is 180°, so m∠K = 180° -45° -30° = 105°.

The Law of Sines tells you

... FL/sin(∠K) = FK/sin(∠L)

Solving for FL, we get

... FL = FK·sin(∠K)/sin(∠L)

... FL = a·sin(105°)/sin(30°) = a·sin(105°)/(1/2)

... FL = 2a·sin(105°) ≈ 1.93185a

6 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is: