TIFF files hold more information than JPEG files. True False
2 answers:
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Answer:
Please find the answer in the attached image.
Explanation:
I wrote this program using JavaScript programming language.
// A function to check tickets
function tickets(user_tickets){
var num_tickets;
if (user_tickets < 5) {
num_tickets = 1;
return ('num_tickets: '+ num_tickets);
}
else {
num_tickets = user_tickets;
return('num_tickets: '+ num_tickets);
}
}
// Testing the tickets function
// With user_tickets = 3, 5, 8, and 1
console.log(tickets(3));
console.log(tickets(5));
console.log(tickets(8));
console.log(tickets(1));
The brute strength method determines if each x and y value satisfies both conditions. To do this, we must iterate through each result in the specified range and insert them into both models.
<h3>What are Elegant mathematical technique?</h3>ALGORITHM :
1. Take the values of all coefficients and SET flag = FALSE
2. Run a FOR loop for x in range (-10, 11). 11 won't be included.
2a. Inside the first FOR, start the y FOR loop in range(-10,11). 11 won't be included
2b. Inside the y FOR loop, check IF for a particular value of x and y both the equations satisfied.
2c. If yes, set flag TRUE and print values of x and y.
2d. ELSE the flag stays FALSE.
END FOR Y
END FOR X
3. Check if flag = FALSE, then print NO SOLUTION
PYTHON CODE :
a=int(input()) #taking input for each coefficient
b=int(input())
c= int(input())
a1= int(input())
b1= int(input())
c1= int(input())
flag = False
for x in range(-10,11): #checking for all values of x in range -10 to 10
for y in range(-10,11): #checking for all values of x in range -10 to 10
if (a x + b y – c == 0) and (a1*x + b1*y - c1 == 0) : #checking if the x and y values satisfy the equation
flag = True #setting the flag if solution is found
print('Solution : x = {-10, 10}, y = {-10, 10}'.format(x,y)) #if they satisfy print x & y
if flag = False : #if flag stays false, that means there is no solution
print('No solution')
OUTPUT : The output is given below.
More about the Elegant mathematical technique link is given below.
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