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Deffense [45]
4 years ago
11

For which points in the same quadrant as(2,-10)could Tamara use a number line to find the distance?

Mathematics
1 answer:
VLD [36.1K]4 years ago
4 0

ANSWER

(2,-2)

(10,-10)

(2,-9)

(7,-10)

EXPLANATION

The given point is (2,-10)

This point is in the fourth quadrant.

To be able to use the number line to find the distance between this point , (2,-10) and another point in the fourth quadrant, the second point must have the same x-coordinate with this point or the same y-coordinate with this point.

These points are:

(2,-2)

(10,-10)

(2,-9)

(7,-10)

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Solve<br>4(2x - 3) = 6x + 2​
vaieri [72.5K]

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4(2x - 3) = 6x + 2

Expand it:

8x - 12 = 6x + 2

+ 12 to both sides

8x = 6x + 14

- 6x from both sides

2x = 14

Divide both sides by  2:

x = 7

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4 0
3 years ago
Need help as soon as possible
alukav5142 [94]

Answer:

D. 70

Step-by-step explanation:

if vx is bisector then 3z - 4 = z + 6 add like terms

2z = 10;and z = 5

To find the perimeter we add all side lengths

VU + UW + WV = 5z - 1 + 5z - 1 + 3z - 4 + z + 6 = 14z

we know z = 5 so 14 × 5 = 70

8 0
3 years ago
A man starts walking north at 5 ft/s from a point P. Five minutes later a woman starts walking south at 6 ft/s from a point 500
aev [14]
Check the picture below.

the man is going North, and he has a rate of 5 f/s, she's going south, 500 miles from P, the green distance, and she's going 6 f/s.

by the time she started walking, he already had been walking for 5 minutes, or 300 seconds, since he's going 5 f/s, then he had already covered 1500 feet by then.

after that, they both walked for 15 minutes more or 900 seconds, and for her that means 5400 feet, whilst for him going slower means 4500 feet, as you see in the  picture.

since he's going North and she's going South, dy/dt is the combined rates, as you see there.

now, let's use the pythagorean theorem, bearing in mind that the green 500 feet are constant all the while, that matters because the derivative of a constant is 0.

\bf r^2=x^2+y^2\stackrel{chain~rule}{2r\cfrac{dr}{dt}}=0+\stackrel{chain~rule}{2y\cfrac{dy}{dt}}\implies \cfrac{dr}{dt}=\cfrac{2y}{2r}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\cfrac{dr}{dt}=\cfrac{y}{r}\cdot \cfrac{dy}{dt}

so, what is "r" value 15 minutes later anyway?

\bf r=\sqrt{(1500+4500+5400)^2+500^2}\implies r=\sqrt{11400^2+500^2}&#10;\\\\\\&#10;r=\sqrt{130210000}\implies r=100\sqrt{13021}

then we just plug those folks in the derivative,

\bf \cfrac{dr}{dt}=\cfrac{y}{r}\cdot \cfrac{dy}{dt}\qquad &#10;\begin{cases}&#10;r=100\sqrt{13021}\\&#10;\frac{dy}{dt}=11\\&#10;y=11400&#10;\end{cases}\implies \cfrac{dr}{dt}=\cfrac{11400}{100\sqrt{13021}}\cdot 11&#10;\\\\\\&#10; \cfrac{dr}{dt}=\cfrac{114\cdot 11}{\sqrt{13021}}\implies  \cfrac{dr}{dt}=\cfrac{1254}{\sqrt{13021}}\implies  \cfrac{dr}{dt}\approx 10.99~\frac{f}{s}

7 0
4 years ago
The ratio of chocolate to caramel in the candy jar is 4:1. If there are 15 caramels in the candy
enot [183]

Answer:

60

Step-by-step explanation:

15 times 4

7 0
3 years ago
Read 2 more answers
A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4
FrozenT [24]
 (–1, 4) to (–4, 1) and <span>(4, 1) to </span><span>(–1, –4)
so
The rule is (x,y) --> (-y,-x)

The reflection over y = - x

hope it helps

</span>
4 0
3 years ago
Read 2 more answers
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