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Zinaida [17]
3 years ago
9

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). Only homozygous individu

als that have two copies of the recessive allele have the condition. If the r allele is found in 15 percent of the population, what's the frequency of the RR genotype?
a. 72.25 percent
b. 12.75 percent
c. 25.5 percent
d. 2.25 percent
Biology
1 answer:
White raven [17]3 years ago
4 0

<span><u>The answer is A. 72.25 percent.</u>

The Hardy-Weinberg principle can be used:</span>

<em>p² + 2pq + q² = 1</em> and <em>p + q = 1</em>

where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq </em>are the frequencies of the genotypes.

<span>The <em>r</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15

To calculate the <em>R</em> allele frequency (<em>p</em>), the formula p + q = 1 is used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85

Knowing the frequency of the <em>R</em> allele (<em>p</em>), it is easy to determine the frequency of the RR genotype (p²):
p² = 0.85² = 0.7225

Expressed in percentage, p² = 72.25%.</span>

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