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svetoff [14.1K]
3 years ago
14

Hal used the following procedure to find an estimate for Step 1: Since and and 81 < 82.5 < 100, is between 9 and 10. Step

2: Since 82.5 is closer to 81, square the tenths closer to 9. Step 3: Since 81.00 < 82.5 < 82.81, square the hundredths closer to 9.1. Step 4: Since 82.5 is closer to 82.62 than it is to 82.44, 9.09 is the best approximation for . In which step, if any, did Hal make an error? In step 1, is between 8 and 10 because 80 and . In step 2, he made a calculation error when squaring. In step 4, he made an error in determining which value is closer to 82.5. Hal did not make an error.
Mathematics
2 answers:
Wewaii [24]3 years ago
8 0

Answer:

4: Since 82.5 is closer to 82.62 than it is to 82.44 this is the wrong estimation.

Step 4 is wrong.

Step-by-step explanation:

Step 1: Since and and 81 < 82.5 < 100, is between 9 and 10.

Step 2: Since 82.5 is closer to 81, square the tenths closer to 9.

Step 3: Since 81.00 < 82.5 < 82.81, square the hundredths closer to 9.1.

Step 4: Since 82.5 is closer to 82.62 than it is to 82.44

So, the last step is wrong. 4: Since 82.5 is closer to 82.62 than it is to 82.44

82.5 is closer to 82.44 not 82.62

aalyn [17]3 years ago
6 0
The answer would be i<span>n step 4, he made an error in determining which value is closer to 82.5</span>
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frez [133]

Answer:

an equilateral triangle

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8 0
3 years ago
Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×
strojnjashka [21]
8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
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Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
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(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
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7.910312934 + 1 = n
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If you want to calculate the number of grains per square inch, you'd use the
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7 0
3 years ago
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Now we'll do the negative version.

2 - x > -4

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4 0
3 years ago
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Anarel [89]
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4 0
2 years ago
Find the perimeter and area of a rectangle with a length of 2 meters and a width of 3 meters
klasskru [66]
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Substituting the given value for the dimensions, 
 
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Therefore, the perimeter is 10m and the area is 6m^2. 




4 0
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