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Furkat [3]
3 years ago
7

−125%+20/28= help plzz

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0
-125%+20/28
-125/100+20/28
ANSWER: -15/28
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Y=(2x-3)^5(2-x^4)^3 differentiate the function please
BARSIC [14]
\bf y=(2x-3)^5(2-x^4)^3\\\\
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\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
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\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
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\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
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5 0
3 years ago
The sum of 2 consecutive integers is –33. If n is the 1st integer, which equation best models the situation?
Masja [62]

Answer:

hard

Step-by-step explanation:

I have never seen this before

8 0
3 years ago
Read 2 more answers
What is th e best estimate for 5 1/9 - 1 5/6
valentinak56 [21]
5 1/9 - 5 5/6 is 3.27, if you want it rounded to the nearest whole number then that would by 3

have a nice day :)
3 0
3 years ago
Let’s now add x to both sides of the equation and consider the new equation x squared+5+x=11
irina1246 [14]

Answer:x=3


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3 0
3 years ago
The base of a triangle exceeds the height by 7 centimeters . If the area is 114 square centimeters, find the length of the base
Ganezh [65]

Answer:

base length = 19 cm  ,  height = 12 cm

Step-by-step explanation:

Area formula  :  A =  (1/2)*b*h

b = h + 7 cm

A = 114 sq. cm

114  =  (1/2) * (h + 7) *h

228 = hh + 7h

hh + 7h - 228 = 0

h = -7/2   +  root( 49 - 4*(-228)) /2

h = -7/2 + 31/2

h = 24/2 = 12 cm

base = 12 cm + 7 cm = 19 cm

5 0
3 years ago
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