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kkurt [141]
3 years ago
9

Every 2/3 hour, Harris can sew 1/6 pair of jeans.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
.25 or 1/4 
i hope that this answer helps you today 

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What is the area of a circle with a radius of 7 inches
Fynjy0 [20]
Area formula is A=πr2 
A=3.1416(radius)2 (radius is 7)
A=3.1416(49) 
A=153.94 
The area is 153.94 inches.
Hope that was helpful :)
7 0
3 years ago
Read 2 more answers
HELP PLZZZZZZZZZZZZ!!!!!!!!!!!!!!!! <br> ILL GIVE YOU 15 POINTS
seropon [69]

Answer:

B

Step-by-step explanation:

a rational number is a number that can be expressed as a fraction p/q of two integers, q cannot be 0

so for A

\sqrt{4/5} Cannot be expressed as 2 integers as a quotient

so A is wrong

For B .125 is 1/8 so yes -2 is a integer so yes 2/5 are 2 integers so yes

and \sqrt{16/9} Is 4/3 so yes

B

7 0
3 years ago
Part A
Anuta_ua [19.1K]

Answer:

Part A: There are 4 zeros of the polynomial function f(x)

Part B: The zeroes of the polynomial function f(x) are -4, -1, 0, 2 ⇒ C

Step-by-step explanation:

<em>The zeroes of a function are </em><em>the x-coordinates of the point of intersection between the graph of the function and the x-axis</em><em> (x-intercepts) which means </em><em>values of x at y = 0</em>

Part A:

In the given graph

∵ The graph of the function f(x) = -x^{4} - 3x³ + 6x² + 8x intersects the x-axis

   at 4 points

→ That means there are 4 values of x have y = 0

∴ The number of zeroes of the function is 4

∴ There are 4 zeros of the polynomial function f(x)

Part B:

∵ The graph intersects the x-axis at points (-4, 0), (-1, 0), (0, 0), (2, 0)

→ That means the values of x at y = 0 are -4, -1, 0, 2

∴ f(x) = 0 at x = -4, -1, 0, 2

∴ The zeroes of the polynomial function f(x) are -4, -1, 0, 2

4 0
2 years ago
What are the solutions of |3x + 2| &gt;9?​
frosja888 [35]

Answer

-11/3>x>7/3

Step-by-step explanation:

|3*7/3+2|=9

|7+2|=9

|9|=9

9=9

therefore, x must be > 7/3

|3*-11/3+2|=9

|-11+2|=9

|-9|=9

9=9

therefore, x must be < -11/3

8 0
3 years ago
(3a2 + 2a - 2) - (a2 - 3a + 7)
drek231 [11]
Remember to distribute invibile -1
simlify 2nd part
-(a^2-3a+7)=-1(a^2-3a+7)=-a^2+3a-7

now we have
3a^2+2a-2-a^2+3a-7=
3a^2-a^2+2a+3a-2-7=
2a^2+5a-9
3 0
2 years ago
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