L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P.
Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2) =>
L2: 2x-y-4=0.............(2)
Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10
=> the point on L1 closest to (2,0) is (19/10, -1/5)
Answer:
56.25 feet
Step-by-step explanation:
225 divided by 4 is 65.25
Same thing is happening to me!
Answer:
D
Step-by-step explanation:
It is because you can see the line pass through the value 0 in x-axis while 6 in y-axis which gives the first coordinate (x,y) = (0,6) and the line also past through the value of 5 in x-axis and 1 in y-axis which gives the second coordinate is (1,5).
So it is true that the line did go through at points (0,6) and (1,5).
