Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
Step-by-step explanation:
Total number of marbles = 5 + 2 + 3 = 10
Probability of choosing 1 green marble = 2/10
Probability of choosing 1 yellow marble = 3/10
Notice (and this is important) that the denominator didn't change. Why?
Because you replaced the first marble into the bag. That word replacement is critical in a problem of this nature. There is the term non replacement which means that the second draw would have a denominator of 9.
So what is the probability of P(green then yellow)?
P(green then yellow) = 3/10 * 2/10 = 6/100
Answer: P(green then yellow) = 3/50 because 6 / 100 reduces.
No. 61 is an odd number not divisible
Answer:
<em>R</em><em>M</em>79 608.51
Step-by-step explanation:
First year,
<em>RM</em>505 050.00×5%=<em>RM</em>505 050.00×5/100
=<em>RM</em>25 252.50
second year,
(<em>RM</em>505 050.00+<em>R</em><em>M</em>25 252.50)×5%=<em>RM</em>530 302.50×5/100
=<em>RM</em>26 515.13
third year,
(<em>R</em><em>M</em>530 302.50+<em>R</em><em>M</em>26 515.13)×5%=<em>R</em><em>M</em>556817.63×5/100
=<em>R</em><em>M</em>27840.88
three years interest,
<em>RM</em>25 252.50+<em>RM</em>26 515.13+<em>RM</em>27840.88=<em>RM</em>79608.51
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