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zalisa [80]
3 years ago
11

Simplify the expression. 6nx+7p-14p+2nx-6x

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
The simplified version would be 8nx - 7p - 6x 
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What is the gcf of 48 and 64
pantera1 [17]
First, make an organized list of the factors for each number. The common factors are 1, 2, 4, 8, and 16, and the greatest of these is 16. So, the greatest common factor or GCF of 48 and 64 is 16.
6 0
3 years ago
At the beach this weekend, the ratio of sandcastles to kites was 3 to 5. If there were 15 kites spotted, how many items were see
Gelneren [198K]

Answer: 24

Step-by-step explanation:

The ratio of sandcastles to kites was 3 to 5 so if 15 kites were spotted that meant that the 5 was multiplied by 3 so then we multiply the 3 by 3. Now there are 9 sandcastles and 15 kites so now we add 9 to 15 to figure out how many items were seen in all. Nine added to 15 equals 24 which means that 24 items were seen in total.

6 0
3 years ago
Which of the following equations is the result of completing the square on x^2 - 6x - 9 = 0?
lina2011 [118]
X² - 6x - 9 = 0
x² - 3x - 3x - 9 = 0
x (x-3) -3(x + 3) = 0
(x - 3)² = 0

In short, Your Answer would be Option A

Hope this helps!
6 0
3 years ago
Read 2 more answers
OK I'm really confused.
pickupchik [31]

Answer:

i am pretty sure the answer is UT.

Step-by-step explanation:

this is because all the letters have linear connections to the other letter, all except UT do.

i hope this helps, tell me if this is wrong.

8 0
3 years ago
Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate
kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality x^{2}-5x+4\leq 0. To do that, factorize, then we have that (x-4)(x-1)\leq 0. This implies that

x-1\leq 0\, \text{and}\, x-4\geq 0

or

x-1 \geq 0\, \text{and}\, x-4\leq 0

In the first case the solution is the empty set \emptyset. In the second case the solution is the interval 1\leq x \leq 4. Now we have that

A=[1,4]

B=(3,5)

C=(3,4].

To show that A\cap B\subseteq C consider x\in A\cap B. Then 1\leq x \leq 4\, \text{and}\, 1, this implies that 3, then x\in C. Now, to show that C\subseteq A\cap B consider x\in C, then 3, then 1\leq x \leq 4\, \text{and}\, 3, then x\in [1,4] \, \text{and}\, x\in (3,5), this implies that x\in A\cap B.

Observe the image below.

7 0
3 years ago
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