Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
The LCM of 5, 6, and 9 is the product of all prime numbers on the left, i.e. LCM(5, 6, 9) by division method = 2 × 3 × 3 × 5 = 90.
Answer:
Q=(0.4.-1.7)
R=(2.4. 9.3)
S=(-10.6. 7.3)
Step-by-step explanation:
Just did it and got it wrong and these are the correct answers
