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ch4aika [34]
3 years ago
15

Lines of latitude range from ___ to ___, lines of longitude range from ___ to ___

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

Step-by-step explanation: Lines of latitude range from north to south, lines of longitude range from east to west

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32 athletes are going camping for the weekend. Three athletes can sleep in one tent. What is the minimum number of tents that wi
Yuliya22 [10]

Answer:

11

Step-by-step explanation:

6 0
3 years ago
The 7th grade has 386 students. There are 32 more girls than boys in the grade how many boys are in the 7th grade
alexandr402 [8]

Answer:

there are 161 boys and 225 girls.

8 0
3 years ago
Read 2 more answers
PQ has a midpoint of M. the coordinates of M are (-4, 7) and the coordinates of P are (2, 13). What are the coordinates of Q?
Natali5045456 [20]

Using the midpoint formula, the coordinates of Q are: <em>A. (-10, 1)</em>

<h3>What is the Midpoint Formula?</h3>
  • Midpoint formula is given as, M(x, y) = (\frac{x_2 + x_1}{2} , \frac{y_2 + y_1}{2})

Thus, given that:

  • M is the midpoint of PQ.
  • M (-4, 7)
  • P (2, 13).

Therefore:

M(-4, 7) = (\frac{2 + x_1}{2} , \frac{13 + y_1}{2})

Solve for x-coordinate of P:

-4 = 1/2(2 + x1)

2(-4) = 2 + x1

-8 = 2 + x1

-8 - 2 = x1

x1 = -10

Solve for y-coordinate of P:

7 = 1/2(13 + y1)

14 = 13 + y1

y1 = 1

Therefore, using the midpoint formula, the coordinates of Q are: <em>A. (-10, 1)</em>

<em />

Learn more about the midpoint formula on:

brainly.com/question/88621

3 0
3 years ago
In the figure, BCND is a rectangle and CGNR is a rhombus. The area of BCND is 90 and BC = 10. What is 3GR?
PIT_PIT [208]

Answer:

3GR=27


Step-by-step explanation:

<u>Since area of rectangle BCND is given as 90 and one of its side is 10, the other side MUST be 9.</u>

<u>CN*BC=90\\CN*10=90\\CN=9</u>


In Rhombus CGNR, CN and GR are congruent (property of Rhombus). Hence GR = 9 as well.

Thus 3GR = 3(9) = 27

First answer choice is right.


6 0
4 years ago
Please help me solve this geometry problem:)
yarga [219]

Given:

The endpoints of a line segment are (-5,12) and (-5,0).

To find:

The coordinates of a points which divides the line segment in 2:1.

Solution:

Section formula: If a point divides a line segment in m:n.

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Let point P divides the given line segment in 2:1. They, by using section formula, we get

P=\left(\dfrac{2(-5)+1(-5)}{2+1},\dfrac{2(0)+1(12)}{2+1}\right)

P=\left(\dfrac{-10-5}{3},\dfrac{0+12}{3}\right)

P=\left(\dfrac{-15}{3},\dfrac{12}{3}\right)

P=\left(-5,4\right)

Therefore, the coordinate of the point that partitions the given segment in the ratio 2:1 are (-5,4).

8 0
3 years ago
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