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Feliz [49]
3 years ago
5

True or false variable is a letter used in place of a number

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
Answer: TRUE!


Variables ARE letters used in place of numbers absolutely
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Help!!!!!! Find x and y so the quadrilateral is a parallelogram.
iren [92.7K]

Answer:

Conclusion:

  • The value of x = 7
  • The value of y = 4

Step-by-step explanation:

Given

  • The parallelogram PQRS

We know that the diagonals of a parallelogram bisect each other.

Therefore,

  • RT = TP

Given RT = x and TP = 5x-28, so

x = 5x-28

5x = x+28

5x-x = 28

4x = 28

divide boh sides by 4

4x/4 = 28/4

x = 7

Thus, the value of x = 7

Similarly,

QT = TS

Given QT = 5y and TS = 2y+12, so

5y = 2y+12

5y-2y = 12

3y = 12

divide both sides by 3

3y/3 = 12/3

y = 4

Thus, the value of y = 4

Conclusion:

  • The value of x = 7
  • The value of y = 4
3 0
2 years ago
-4x-y=24<br> whats the missing value
lubasha [3.4K]

Answer:

x

Step-by-step explanation:

;\

4 0
3 years ago
the stemplot below represents the distribution of the test scores for the final exam in a high school algebra course. what was t
Deffense [45]

Answer:

<u><em></em></u>

  • <u><em>Option A. 94</em></u>

Explanation:

The column of digits to the left (before the vertical line) contains the largest place-value digits.

Here is how you read the values:

  • First row: 65

  • Second row: 73, 74, 78

  • Third row: 80, 80, 81, 82, 85, 88, 89

  • Fourth row: 92, 93, 94.

Thus, the highest score received is 94.

8 0
2 years ago
Help me its due today
Tanzania [10]

Answer:

$65.35

Step-by-step explanation:

  1. First you have to divide 5.4% by 100
  2. Take 5.4/100 and multiply it by 62
  3. Take the number you get from step 2 and add it to 62! (:
4 0
3 years ago
What is the range of the function y = 2sin X?
ruslelena [56]

Answer:

Range: [-2, 2] {y | -2 ≤ y ≤ 2}

Step-by-step explanation:

The given function is y = 2sinx

We have to find the range of the given function.

Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]

and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]

So range of y = 2sinx is [-2, 2]

7 0
2 years ago
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