Answer:
I = p× r× t
300×8×4
pinicipal × rate × time
That is the formula
the answer is 300×8×4= 9600
Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
is 4.
Then, 7(-2) is -14.
Then, 4 - (-14) is (-18).
Finnaly, (-18) - 8 is
[-26]
9514 1404 393
Answer:
7.5 square units
Step-by-step explanation:
The formula for the area of a trapezoid is ...
A = 1/2(b1 +b2)h
where b1 and b2 are the lengths of the parallel bases, and h is the perpendicular distance between them.
Here, the bases are TR = 1 and PA = 4. The height is 3 units, so the area is ...
A = (1/2)(1 +4)(3) = 15/2 = 7.5 . . . . square units
