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3 years ago

A protein with quaternary structure contains four domains.

1 answer:

5 0

The answer is true:Even such small proteins contain hundreds of atoms and have molecular protein structure in terms of four levels ......

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A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68

FinnZ [79.3K]

First of all, as you seen the gases are noble which means that will not react with each other and in this case each gas create individual pressure.

P $_{T}$ = total pressure

P $_{Ne}$ = pressure of neon

P $_{Ar}$ = pressure of argon

P $_{He}$ = pressure of helium {which is required}

P $_{T}$ = P $_{Ne}$ + P $_{Ar}$ + P $_{He}$

1.25 = 0.68 + 0.35 + P $_{He}$

P $_{He}$ = 1.25 - [0.68 + 0.35] = 0.22 atm

4 0

3 years ago

What are the coefficients that belong in the blanks to balance the following chemical equation?

brilliants [131]

Answer:

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

Explanation:

silver(I) iodide + sodium sulfide ⟶ silver(I) sulfide + sodium iodide

1. Convert the word equation to a chemical equation:

AgI + Na₂S ⟶ Ag₂S + NaI

2. Put a 1 in front of the most complicated-looking formula (Na₂S?):

AgI + 1Na₂S ⟶ Ag₂S + NaI

3. Balance Na:

We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaI.

AgI + 1Na₂S ⟶ Ag₂S +2NaI

4. Balance S:

We have fixed 1 S on the left. We need 1 O on the right. Put a 1 in front of Ag₂S.

AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

5. Balance Ag:

We have fixed 2Ag on the right. We need 2 Ag on the left. Put a 2 in front of AgI.

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

Every formula now has a coefficient. The equation should be balanced.

6. Check that atoms balance:

Atom On the left On the right

Ag 2 2

I 2 2

Na 2 2

S 1 1

The balanced equation is

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

4 0

4 years ago

What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(l), and molten m

Afina-wow [57]

The substance that is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(I), and molten magnesium iodide, mgi2(I), can be expressed as Ca2+ + 2eâ’ --> Ca. At the anode, the substance can be expressed as 2Brâ’ â’ 2eâ’ --> Br2. At the cathode for magnesium iodide can be expressed as Mg2+ + 2 eâ’ --> Mg, and 2 Iâ’ â’ 2 eâ’ --> I2 at the anode.

5 0

4 years ago

Suppose that the saturation magnetization Mmax of the ferromagnetic metal nickel is 4.41 × 105 A/m. Calculate the magnetic momen

Lady bird [3.3K]

Answer : The magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

Explanation :

Formula used :

$M_{max}=(\frac{N}{V})\times \mu$

where,

$M_{max}$ = saturation magnetization = $4.41\times 10^5A/m$

N = Avogadro's number = $6.022\times 10^{23}atoms/mol$

V = volume of nickel atom

$\mu$ = magnetic moment

First we have to calculate the volume of nickel atom.

$Density=\frac{Mass}{Volume}$

$8.90g/cm^3=\frac{58.71g/mol}{Volume}$

$Volume=\frac{58.71g}{8.90g/cm^3}$

$Volume=6.59cm^3=6.59\times (100)^3m^3$

Now we have to calculate the magnetic moment of a single nickel atom.

$M_{max}=(\frac{N}{V})\times \mu$

$4.41\times 10^5=(\frac{(6.022\times 10^{23})}{6.59})\times (100^3)\times \mu$

$\mu=4.82\times 10^{-24}Am^2$

Therefore, the magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

7 0

3 years ago

How many atoms of nitrogen are present in 2.49 moles of nitrogen trifluoride ? atoms of nitrogen?

stepladder [879]

Nitrogen trifluoride - NF3.
1 mol NF3 contains 1 mol atoms of Nitrogen
2.49 mol NF3 contains 2.49 mol atoms of Nitrogen

1 mol ---- 6.02 *10²³ atoms
2.49 mol ----- 2.49*6.02*10²³ = 15.0*10²³ atoms of N

6 0

3 years ago