Yes (Al) Aluminum and (S) Sulfur would make an ionic compound because you need a metal and a nonmetal to make an ionic compound.
Answer:
evaporation
Explanation:
Evaporation occurs when a liquid changes to a gas. During evaporation, molecules gain enough thermal energy to escape from the liquid surface into the air as water vapor.
hope this helps
Answer:
pH = 8.477
Explanation:
∴ ni 0.3 - -
nf - 0.3 0.3
∴ ni 0.50 - 0.3
nf 0.5 - X X 0.3 + X
∴ Ka = 2.0 E-9 = ([H3O+]*[OBr-]) / [HOBr]
⇒ Ka = 2.0 E-9 = ((X/1L)*(0.3 + X)/1 L) / ((0.5 - X)/1L)
⇒ 2.0 E-9 = ( 0.3X + X² ) / (0.5 - X)
⇒ X² + 0.3X - 1 E-9 = 0
⇒ X = 4.333 E-9 M
according Henderson-Hauselbach:
- pH = pk + Log [A-] / [HA]
∴ [OBr-] = 0.3 mol/ 1 L + 4.333 E-9 M = 0.300 M
∴ [HOBr] = 0.5 mol / 1 L - 4.33 E-9 M = 0.500 M
∴ pKa = - log Ka = - Log ( 2.0 E-9 ) = 8.6989
⇒ pH = 8.6989 + Log ( 0.300/0.500 )
⇒ pH = 8.477
<span>the balanced equation for the reaction is as follows ;
Na</span>₂S + 2AgNO₃ ---> 2NaNO₃ + Ag₂<span>S
stoichiometry of Na</span>₂S to AgNO₃<span> is 1:2
number of AgNO</span>₃<span> moles reacted - 0.315 mol/L x 0.04000L = 0.0126 mol according to molar ratio of 1:2
number of Na</span>₂S moles required are - 1/2 x number of AgNO3 moles reacted Na₂<span>S moles = 0.0126 mol /2 = 0.00630 mol
molarity of Na</span>₂<span>S - 0.260 M
there are 0.260 mol in 1 L
therefore 0.00630 mol are in - 0.00630 mol / 0.260 mol/L
volume of Na</span>₂<span>S required = 0.0242 L
volume of Na</span>₂S required = 24.4 mL