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Gennadij [26K]
3 years ago
12

How do you know what number to multiply everything by using the elimination method on systems of equations??

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

See below  

Step-by-step explanation:

You multiply the equations by numbers that will give you the least common multiple of the coefficients.

Suppose you have a system of two equations:

\begin{cases}(1)& 2x + y = 40\\(2) & x + 2.5y = 60\end{cases}\\

You can choose to eliminate either x or y.

1. Eliminating x

The coefficients of x are 2 and 1. The least common multiple is 2, so you multiply (1) by 1 and (2) by 2 to get

\begin{array}{lrcll}(3) & 2x + y & = & 40 &\ \\(4) & 2x + 5y & = & 120 & }\\\end{array}

Then you can subtract (3) from (4) and get

4y = 80. Solve for y.

2. Eliminating y

The coefficients of y are 1 and 2.5. The least common multiple is 2.5, so you multiply (1) by 2.5 and (2) by 1 to get

\begin{array}{lrcll}(5) & 5x + 2.5y & = & 100 &\ \\(6) & x + 2.5y & = & 60 & }\\\end{array}

Then you can subtract (6) from (5) and get

4x = 40. Solve for x.

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Verify that your point from Question 2 is a solution to 2x-y=-12x−y=−1 AND is also a solution to y=5x-5y=5x−5. What does it mean
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(b) They are simultaneous equations

Step-by-step explanation:

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Required

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<em>Because both sides of the equation are equal, then the point is a solution</em>

<em></em>

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<em>Because both sides of the equation are equal, then the point is a solution</em>

<em></em>

<em></em>

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