Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
m5=75 degrees
m11=75 degrees
m16=65 degrees
To find 5, realize angles 5 and 8 equal 180, because they make up a straight line, line d.
180-105=75
To find 11, it is the same as finding 7. Just look at the similar sizes. Angle 7 is the same at angle 5, just turned around. There’s a term for this pair angles that I don’t remember now but it exists. Now, lines a and b are parallel, so their angles between lines that intersect both are the same too. This means, as angle 5 equals angle 7, angle 7 equals angle 11.
To find 16, we use a combination of the methods used in finding the previous angles.
180-115=65 degrees is angle 4
Angle 4=Angle 16
Knowing the two angles given and that lines a and b are parallel, you could find the measurements of every angle in each intersection if you wanted to.
Answer:
I hope this is correct but 8.5 or 8 1/2 Units
Answer:
20
Step-by-step explanation:
1449÷72.45=20
