Simplify the expressions below 1) 2x + 5 – 3y – 7x + y -8 Please simplify

Mathematics

1 answer:

larisa86 [58]4 years ago

6 0

Answer:

−5x − 2y − 3

Explanation:

2x + 5 − 3y − 7x + y − 8

= 2x + 5 + −3y + −7x + y + −8

[ Combine Like Terms ]

= 2x + 5 + −3y + −7x + y + −8

= (2x + −7x) + (−3y + y) + (5 + −8)

= −5x + −2y + −3

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NEED HELP RIGHT NOW !!!!!!!!!!!!!!!!!!!!!!!!!

kykrilka [37]

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$\large\sf\begin{gathered} \begin{bmatrix} {2 } \: \: \: \: \: 3 \: \\1 \: \: \: \: 4\\ \end{bmatrix}\end{gathered} \: \: \large = 2 \times 4 + 3 \times 1 \\ \large = 8 + 3 \\ \underline{ \boxed{ \large\bf\red{= 11}}} ✓$

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8 0

2 years ago

Whats the answer and how do i get the answer myself

Mumz [18]

Answer:

$f^{-1} (x) = \frac{x}{3} - 3$

Step-by-step explanation:

Let here the given function f(x) = y

or, $x= f^{-1} (y)$

⇒ y = 3x+ 9

Now, solving for x, we get

3x+ 9 = y ⇒ 3x = y - 9

or, $x = \frac{y-9}{3} = \frac{y}{3} - \frac{9}{3}$

⇒ $x = ( \frac{y}{3}) - 3$

Now, substituting x and y

Hence, $f^{-1} (x) = \frac{x}{3} - 3$

3 0

3 years ago

What is the standard form of the equation of the circle in the graph

seraphim [82]

The standard form of the equation of a circle with center (h, k) and radius r is
(x-h)² + (y-k)² = r²

You have a circle centered at (-3, 1) with radius 1, so the standard form equation is
(x+3)² + (y-1)² = 1