16r^2+ 2r -4r
16r^2 - 2r
2r ( 8r -1)
A positive plus a negative will equal a negative #.
1+-2= -1
Answer:
where is the hint
Step-by-step explanation:
you might want to try reading the hint
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
Answer and explanation:
Given : The position of an object moving along an x axis is given by where x is in meters and t in seconds.
To find : The position of the object at the following values of t :
a) At t= 1 s
b) At t= 2 s
c) At t= 3 s
d) At t= 4 s
(e) What is the object's displacement between t = 0 and t = 4 s?
At t=0, x(0)=0
At t=4, x(4)=14.24
The displacement is given by,
(f) What is its average velocity from t = 2 s to t = 4 s?
At t=2, x(2)=-1.76
At t=4, x(4)=14.24
The average velocity is given by,